What is constant velocity in comparison to instantaneous velocity?

Physics

1 answer:

sergij07 [2.7K]3 years ago

8 0

Answer:

Please find the answer in the explanation

Explanation:

Constant velocity is the uniform velocity. That is, the velocity is steady and it does not change. You will have a constant velocity when you maintain a certain velocity for a long time without changing it.

At constant velocity, acceleration is equal to zero.

Instantaneous velocity is the change in distance in a specific direction per specific time. It is a velocity at a certain time. It is not uniform.

Change in instantaneous velocity is equal to acceleration.

You might be interested in

A neutron has

zavuch27 [327]

Answer:

Explanation:

a neutron does not have a positive nor negative charge it remains neutral

6 0

3 years ago

Read 2 more answers

LABORATORY TITLE:

mezya [45]

Answer:

PAPER CLIPS ON NOSE OF A PAPER AIRPLANE

Purpose: To determine if the number of paperclips on the nose of a paper airplane affects the velocity and speed, measured in meters per seconds.

Make a Hypothesis Based on the Learning Thus Far: If the number of paperclips on the nose of a paper airplane increases, then the speed will _increase______ (increase, decrease, stay the same) in a __linear_______ (linear, exponential, logarithmic) mathematical relationship, and the velocity will (increase, decrease, stay the same) in a __exponential____ (linear, exponential, logarithmic) mathematical relationship. (Fill in the appropriate words for your hypothesis.)

Pictures: Insert at least 3 pictures of yourself conducting the experiment into this lab report. At least 2 pictures must show your face as you conduct the investigation. You may need to ask someone to help take these photos.

Explanation:

5 0

3 years ago

he atomic radii of Li and O2- ions are 0.068 and 0.140 nm, respectively. (a) Calculate the force of attraction in newtons betwee

Crazy boy [7]

Answer:

$F = -1.07 *10^{-8} \ N$

$F_r = 1.07 *10^{-8} \ N$

Explanation:

Generally the force of attraction between this two irons is mathematically represented as

$F = \frac{k * [Q_{Li} ] * [Q_{O} ] }{ r^2}$

Here k is known as the proportionality constant with value $k = 2.31 * 10^ {-28} J \cdot m$

substituting -2 for $Q_{O}$ i.e the charge on oxygen , +1 for $Q_{Li}$ i.e the charge on Lithium and $[0.140 + 0.068 ] nm= 0.208 nm = 0.208*10^{-9}$ for r