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g100num [7]
3 years ago
15

A floating ice block is pushed through a displacement d = (14 m) i hat - (11 m) j along a straight embankment by rushing water,

which exerts a force F = (158 N) i hat - (179 N) j on the block. How much work does the force do on the block during the displacement?
Physics
1 answer:
Alika [10]3 years ago
7 0

Explanation:

Given that,

Displacement in ice block, d=14i-11j

Force exerted by water, F=158i-179j

To find,

Work done by the force during the displacement.

Solve,

We know that the product of force and displacement is called work done. It is also equal to the dot product of force and displacement as :

W=F.d

W=(158i-179j).(14i-11j)

We know that, i.i = j.j = k.k = 1

W=2212+1969=4181\ J

So, the work done by the force on the block during the displacement is 4181 Joules.

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We place a small pressure sensor at a certain depth in water. with which orientation does the sensor register the greatest press
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4 years ago
A 85.0kg man and a 65, 0kg woman are riding a Ferris wheel with a radius of 20.0m. What is the Ferris wheels tangential velocity
zvonat [6]

Answer:

The Ferris wheel's tangential (linear) velocity if the net centripetal force on the woman is 115 N is <u>3.92 m/s</u>.

Explanation:

Let's use <u>Newton's 2nd Law</u> to help solve this problem.

  • F = ma

The force acting on the Ferris wheel is the centripetal force, given in the problem: F_c=115 \ \text{N}.

The mass "m" is the <u>sum</u> of the man and woman's masses: 85+65= 150 \ \text{kg}.

The acceleration is the centripetal acceleration of the Ferris wheel: a_c=\displaystyle \frac{v^2}{r}.

Let's write an equation and solve for "v", the tangential (linear) acceleration.

  • \displaystyle 115=m(\frac{v^2}{r} )
  • \displaystyle 115 = (85+65)(\frac{v^2}{20})
  • \displaystyle 115=150(\frac{v^2}{20} )
  • .766667=\displaystyle(\frac{v^2}{20} )
  • 15.\overline{3}=v^2
  • v=3.9158

The Ferris wheel's tangential velocity is 3.92 m/s.

8 0
2 years ago
The capacitance of a capacitor depends on what?​
bonufazy [111]

Answer:

The capacitance of a capacitor depends on the charge and voltage of a system. It is also dependent, if present, on the dielectric as well.

General Formulas and Concepts:
<u>Gauss's Law</u>

Capacitance Formula: \displaystyle C = \frac{Q}{V}

  • <em>Q</em> denotes charge
  • <em>V</em> denotes voltage

Dielectric Capacitance Formula:  \displaystyle C = \kappa C_0

  • <em>C₀</em> denotes original capacitance
  • <em>κ</em> denotes the dialectic constant

Explanation:

A <u>capacitor</u> <em>stores</em> charge when run through an electrical current. The <u>capacitance</u> is <em>how much </em>charge a capacitor can hold.

We can define the relationship of capacitance by using the formula. Capacitance is <em>inversely proportional</em> to the potential energy, or <u>voltage</u>, of the system. Therefore, you will need to know what the <u>charge</u> Q of the system as well has voltage V in order to find the capacitance.

If there is a dielectric involved inside the capacitance, you also must incorporate the value of the <u>dielectric constant </u>into your capacitance. A dielectric is <em>directly proportional </em>to the capacitance; the bigger the dielectric constant, the bigger capacitance, as denoted in our equation.

Topic: AP Physics C - EMAG

Unit: Gauss's Law

5 0
3 years ago
How can an object become charged
morpeh [17]

Answer:

An object gets charged when it's atoms lose or gain an electron to become an ion. For example: ... This means that the fur loses it's electrons to the plastic rod and both objects are now charged. The fur is positively charged because it lost electrons and the rod is negatively charged because it gained electrons

Explanation:

comment how it helps

3 0
3 years ago
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