Answer:
The induced current is 26.7 mA
Explanation:
Given;
area of the loop, A = 0.078 m²
initial magnetic field, B₁ = 3.8 T
change in the magnetic field strength, dB/dt = 0.24 T/s
The induced emf is calculated as;

The resistance of the loop = 0.7 Ω
The induced current is calculated as;

Answer:

Explanation:
magnetic flux is the count of magnetic field lines passing through a given loop or area
As we know that magnetic flux is given by the formula

here we also know that magnetic field B and plane of the coil is perpendicular in initial position
So the area vector is always perpendicular to the plane of the coil
so the angle between magnetic field and area vector is parallel to each other and this angle would be zero
so magnetic flux of the coil initially we have

Answer:
103.1 V
Explanation:
We are given that
Initial circumference=C=168 cm

Magnetic field,B=0.9 T
We have to find the magnitude of the emf induced in the loop after exactly time 8 s has passed since the circumference of the loop started to decrease.
Magnetic flux=
Circumference,C=

cm



When t=0



E=

t=8 s
B=0.9


Kinetic energy is the energy the makes an object move.
Answer
given,
given,
small cube side = 10 cm
larger cube side = 12 cm
density of steel = 7 g/cm³
density of aluminium = 2.7 g/cm³
density of the water (ρ₁)= 1 g/cm³
Cube A and B made of steel
buoyant force of Cube A
B₁ = ρ₁ V g = 1 x 10 x 10 x 10 x g= 1000 g
for cube B
B₂ = ρ₁ V g = 1 x 12 x 12 x 12 x g= 1728 g
buoyant force of Cube C
B₃ = ρ₁ V g = 1 x 10 x 10 x 10 x g= 1000 g
for cube D
B₄ = ρ₁ V g = 1 x 12 x 12 x 12 x g= 1728 g
buoyant force acting on the cube depends on the density of the fluid
hence,
B₂ = B₄ > B₁ = B₃