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faltersainse [42]
3 years ago
13

Which of the following statements about electric charges and magnetic domain is true?

Chemistry
2 answers:
Brums [2.3K]3 years ago
5 0
C hope i was able to help
saw5 [17]3 years ago
3 0
The correct answer is C. Magnetic domains must come in pairs one north one south. I took the test.
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The sun of the protons a D neutrons in the nucleus of an atom is called the ATOMIC MASS
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How many grams of salt are in 5 l of a solution with a concentration of 3 g/L
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Answer: 15 grams of salt are there in 5 L of solution.

Explanation:

Concentration of a solution is defined as the number of grams of solute dissolved per liter of the solution.

Given : Concentration of solution : 3 g/L

1 Liter of solution contains = 3 gram of salt

Thus 5 L of solution contains = \frac{3g}{1L}\times 5L=15g

Thus 15 grams of salt are there in 5 L of solution.

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All of the atoms of argon have the same
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4 years ago
Suppose a sample of gas is composed of 100 molecules, with speeds given below. Speed (m/s) Number 200 23 400 42 600 26 800 8 100
ollegr [7]

Answer:

The answer is:

speed(\frac{m}{s}) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (number)\\\\ 100 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 23  \\\\ 200 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 42  \\\\ 300 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 26  \\\\ 400 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 8  \\\\ 500 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1  \\\\

Explanation:

Its total kinetic energy of a gas colloquial atom colloction is equal to absolute temperature alone, according to the programs that directly gas Theory.

Average speed for 1st option:

= \frac{(200 \times 23)+(400 \times 42)+(600 \times 26)+(800 \times 8) +1000}{100} \\\\= 444\  \frac{m}{s} \ \ \ \  \ \ \ \ \ \text{average speed of gas}

 Average speed for 2nd option:

 = \frac{(200 \times 11) +(400 \times 21)+ (600 \times 13)+ (800 \times 4)}{11+21+13+4} \\\\= 440 \ \frac{m}{s}

 Average speed for 3rd option:

= \frac{(200 \times 43) +(400 \times 50)+ (600 \times 7)}{100} \\\\ =328 \ \frac{m}{s}

 Average speed for 4th option:

 = \frac{(200 \times 50) +(400 \times 25)+ (600 \times 13)+(800\times 8)+(1000 \times 4)}{100}\\\\ =382\  \frac{m}{s}

  Average speed for 5th option:

= \frac{(100 \times 23) +(200 \times 42)+ (300 \times 26)+(400\times 8)+500}{100}\\\\ =222 \ \frac{m}{s}

The average speed also increased by half because the temperatures had kinetic energy.\to 444 \ \frac{m}{s}\  to \ 222 \ \frac{m}{s}

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3 years ago
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