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andre [41]
3 years ago
6

How many Zn atoms are there in 4.65 moles of Zn?

Chemistry
1 answer:
Nesterboy [21]3 years ago
8 0
So your answer would pretty much be 2.80 x 10^24. The picture is just the explanation and how you would get that answer.

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15. Triglycerides, waxes, and steroids are all ___ lipids because they contain only carbon, hydrogen, and oxygen
Jlenok [28]
The answer to this question is C
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The chemical formula for strontium sulfite is SrSO3.<br><br><br> TRUE<br><br><br> FALSE
VLD [36.1K]
Valency is the number of electrons lost or gained by an atom to attain an stable configuration. Valency is important when writing the formula of chemical compounds in chemistry. Strontium has a valency of  2 while sulfite ion (radicle) has a valency of 2. Therefore, the chemical formula of strontium sulfite is written as SrSO3.
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3 years ago
A reaction occurs in a calorimeter, resulting in the starting and final temperatures shown below. What can you say about the rea
Pavlova-9 [17]

Answer:

The reaction is exothermic and ΔH is negative

Explanation:

An exothermic reaction is a chemical reaction that releases energy in the form of heat. It is the opposite of an endothermic reaction in which energy is absorbed. It is expressed in a general thermochemical equation: reactants → products + energy.

We can know that a reaction is exothermic by observing the calorimeter to know if there is an increase in temperature. Remember that an exothermic reaction leads to evolution of heat. This is observed physically as a rise in temperature.

The calorimeter initially read 21.0 and finally read 38.8 at the end of the reaction. This implies that heat was given out in the process. The reaction is exothermic and ∆H is negative.

8 0
4 years ago
Question 54
dusya [7]
I really hope and think it’s E
7 0
3 years ago
The rate constants of some reactions double with every 10-degree rise in temperature. Assume that a reaction takes place at 295
LUCKY_DIMON [66]

Answer : The activation energy for the reaction is, 51.9 kJ

Explanation :

According to the Arrhenius equation,

K=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = rate constant at 295 K

K_2 = rate constant at 305 K = 2K_1

Ea = activation energy for the reaction = ?

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 295 K

T_2 = final temperature = 305 K

Now put all the given values in this formula, we get:

\log (\frac{2K_1}{K_1})=\frac{Ea}{2.303\times 8.314J/mole.K}[\frac{1}{295K}-\frac{1}{305K}]

Ea=51879.96J=51.9kJ

Therefore, the activation energy for the reaction is, 51.9 kJ

8 0
4 years ago
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