Answer:
(2R,3S)-2-ethoxy-3-methylpentane
and
(2S,3S)-2-ethoxy-3-methylpentane
Explanation:
For this case, we will have as nucleophile. Also, this compound is also in excess. So, we will have as solvent
a protic solvent. Therefore the Sn1 reaction would be favored.
The first step would be the carbocation formation followed by the attack of the nucleophile. In this case both isomers would be produced: R and S (see figure).
<u>Answer:</u> The concentration of chloride ions in the solution obtained is 0.674 M
<u>Explanation:</u>
To calculate the number of moles for given molarity, we use the equation:
.....(1)
Molarity of KCl solution = 0.675 M
Volume of solution = 297 mL
Putting values in equation 1, we get:
1 mole of KCl produces 1 mole of chloride ions and 1 mole of potassium ion
Moles of chloride ions in KCl = 0.200 moles
Molarity of magnesium chloride solution = 0.338 M
Volume of solution = 664 mL
Putting values in equation 1, we get:
1 mole of magnesium chloride produces 2 moles of chloride ions and 1 mole of magnesium ion
Moles of chloride ions in magnesium chloride =
Calculating the chloride ion concentration, we use equation 1:
Total moles of chloride ions in the solution = (0.200 + 0.448) moles = 0.648 moles
Total volume of the solution = (297 + 664) mL = 961 mL
Putting values in equation 1, we get:
Hence, the concentration of chloride ions in the solution obtained is 0.674 M
