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crimeas [40]
3 years ago
5

The diagram to the right shows a gas with an intital pressure of 3060 mmhg inside a cyinder

Chemistry
1 answer:
lord [1]3 years ago
5 0
B. 784 mmHg

~ hope this helps!
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Whats the correct order of these?
Igoryamba
1109, 5.9 * 10 squared, -0.041, -4.2 times 10 to the -3, and -7.6 times 10 to the -5
Hope this helps
3 0
3 years ago
An airplane starts at rest and Excelerator down the runway for 20 seconds. At the end of the runway, its velocity is 80 m/s Nort
masha68 [24]
According to the formula you have given us to work with . . .

1). The airplane's acceleration is

(80 m/s north - zero) / (20 sec) = 4 m/sec^2 north

2).  For the cyclist:

                                          (V-final - zero) / 20sec = 0.5 m/s^2 south

Multiply each side by 20s :  V-final = 0.5 m/s^2 south x (20sec) = 

                                                                                         10 m/s south

8 0
3 years ago
Consider the reaction 2CO * O2 —> 2 CO2 what is the percent yield of carbon dioxide (MW= 44g/mol) of the reaction of 10g of c
Arturiano [62]

Answer:

Y = 62.5%

Explanation:

Hello there!

In this case, for the given chemical reaction whereby carbon dioxide is produced in excess oxygen, it is firstly necessary to calculate the theoretical yield of the former throughout the reacted 10 grams of carbon monoxide:

m_{CO_2}^{theoretical}=10gCO*\frac{1molCO}{28gCO}*\frac{2molCO_2}{2molCO}  *\frac{44gCO_2}{1molCO_2}\\\\ m_{CO_2}^{theoretical}=16gCO_2

Finally, given the actual yield of the CO2-product, we can calculate the percent yield as shown below:

Y=\frac{10g}{16g} *100\%\\\\Y=62.5\%

Best regards!

8 0
3 years ago
What viral components might serve as good targets for the design of antiviral chemicals?
densk [106]
Specific events in virus replication identified as targets for antiviral agents are viral adsorption, penetration, uncoating, and viral nucleic acid synthesis as well as viral protein synthesis.

8 0
2 years ago
A 0.245-L flask contains 0.467 mol co2 at 159 °c. Caculate the pressure using Van der Walls equation
AlladinOne [14]

Answer:

The right answer is "60.56 atm".

Explanation:

As we know,

Vander wall's equation is:

⇒ (P+\frac{n^2 a}{v^2} )(v-nb)=nRT

or,

⇒ P=\frac{nRT}{(v-nb)}-\frac{n^2 a}{v^2}

Here,

a = 3.59 L² atm mol⁻²

b = 0.0427 L mol⁻¹

By putting the values in the above equation, we get

⇒ P=\frac{0.467\times 0.0821\times 432}{0.245-0.467\times 0.0427}

       =\frac{(0.467)^2\times 3.49}{(0.245)^2}

       =73.61-13.05

       =60.56 \ atm

8 0
3 years ago
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