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Daniel [21]
3 years ago
5

The electric force between two charges A. increases with distance between the charges B. increases if either one of charges gets

larger C. increases only if both charges get larger simultaneously D. indicates that the charges have opposite sign qE. none of the above
Physics
1 answer:
beks73 [17]3 years ago
6 0

Answer:

Option (A) , (b) and (d) are correct option

Explanation:

According to Coulomb's law electric force between two charges is given by

F=\frac{1}{4\pi \epsilon _0}\frac{q_1q_2}{r^2}

From the relation we can say that force is directly proportional to magnitude of charges and inversely proportional to distance between them '

So if we increase the distance then force will decrease

Increase if any of the charge get larger

If force is attractive then both the charge will be of different sign and is force is repulsive then both the charges of same sign

From above conclusion we can say that (a), (b) and (d) are correct option

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Displacement is d  



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d = Vi t + 1/2 g t²




-15.3 = 10 t + (-4.9) t²




4.9 t² - 10 t -15.3 = 0  



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A city planner needs to make a model of the city. In real life, the tallest tree in the city is 40 feet tall. The shortest tree
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To solve this you must set up what is called a proportion.  A proportion is a way of comparing two comparing values where one of the four values is missing.  In your problem the missing value is the height of the smallest tree in the model.

To set up a proportion, you need all of your values.  The easiest way to do this is to list them:

Highest tree in real life:  40ft
Highest tree in model:  10ft
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So know you can set your proportion like this:

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(When setting up a proportion, you always want to have the values belong to each other.  For example don't put the height of the small tree in the model underneath the value of the highest tree in real life.)

So know to find what the x values equals, we need to cross multiply.  And then all that's left after that is to solve for x.

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Hope this helps! :)



6 0
3 years ago
PLEASE HELP ME,, I WOULD BE SO HAPPY
Juliette [100K]

Answer:

Energy is force times distance. For your problem, no matter how long you push, the wall still goes nowhere, so there is no obvious energy transfer. so in conclusion, you actually didn't do anything :(

Explanation:

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