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Daniel [21]
3 years ago
5

The electric force between two charges A. increases with distance between the charges B. increases if either one of charges gets

larger C. increases only if both charges get larger simultaneously D. indicates that the charges have opposite sign qE. none of the above
Physics
1 answer:
beks73 [17]3 years ago
6 0

Answer:

Option (A) , (b) and (d) are correct option

Explanation:

According to Coulomb's law electric force between two charges is given by

F=\frac{1}{4\pi \epsilon _0}\frac{q_1q_2}{r^2}

From the relation we can say that force is directly proportional to magnitude of charges and inversely proportional to distance between them '

So if we increase the distance then force will decrease

Increase if any of the charge get larger

If force is attractive then both the charge will be of different sign and is force is repulsive then both the charges of same sign

From above conclusion we can say that (a), (b) and (d) are correct option

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A sinusoidal wave travels along a string. The time for a particular point to move from maximum displacement to zero is 0.13 s. W
vitfil [10]

Answer:

Part a)

T = 0.52 s

Part b)

f = 1.92 Hz

Part c)

speed = 3.65 m/s

Explanation:

As we know that the particle move from its maximum displacement to its mean position in t = 0.13 s

so total time period of the particle is given as

T = 4\times 0.13 = 0.52 s

now we have

Part a)

T = time to complete one oscillation

so here it will move to and fro for one complete oscillation

so T = 0.52 s

Part b)

As we know that frequency and time period related to each other as

f = \frac{1}{T}

f = \frac{1}{0.52}

f = 1.92 Hz

Part c)

As we know that

wavelength = 1.9 m

frequency = 1.92 Hz

so wave speed is given as

speed = wavelength \times frequency

speed = 1.92 \times 1.9

speed = 3.65 m/s

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3 years ago
Function do lappet which faced vultures serve in a temperate grassland
vfiekz [6]
Um this doesn't make since to me since you did not clearly state your awnser
7 0
3 years ago
Read 2 more answers
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topjm [15]

Explanation:

u=166m/s, v=0(at it's highest point final velocity is zero), a=9.8m/s², t=8.6s

by the formula, S=ut+½at².

S=[166×8.6+½.×9.8×(8.6)²]. ...by calculation

S = 1427.6+362.404

S=1790.004m

hope this helps you.

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3 years ago
Is the frictional force the same as the applied force when the net force equals zero?
DerKrebs [107]

Answer:

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Explanation:

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