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Dafna1 [17]
3 years ago
12

4.0 kg objects mive a distance of 7.8 m under the action of a cinstant gorce of 5.6 N. how much work is dine on object?

Physics
1 answer:
alexdok [17]3 years ago
6 0

Answer:

43.68 J

Explanation:

Distance moved= 7.8 m

Force = 5.6 N

Work Done= Distance moved * Force

                   = 7.8 *5.6

                      =43.68 Joules

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Before start of slide velocity will be 14.81 m/sec

Explanation:

We have given coefficient of static friction \mu =0.8

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\Theta =tan^{-1}0.8=38.65^{\circ}

tan{38.65^{\circ}}=0.8

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