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guapka [62]
4 years ago
5

If a person and wheelchair have a combined weight of 185 lb, how much ideal effort

Physics
1 answer:
Sholpan [36]4 years ago
8 0

Answer:

Effort force=824.04 \sin\theta

where \theta is the angle of inclination of the ramp.

Explanation:

The given combined mass of a person and wheelchair is 185 lb.

In SI unit, 1 pound= 0.453592 kg

So, 185 lb=185\times0.453592 kg=84kg (approximately)

Assuming the whole mass as a point mass and denote it by M, so

M=84kg

Let the angle of inclination of the ram with the is \theta with respect to the ground and assume that the friction offered by ram id negligible, so neglection the frictional force.

The applied effort force, F, will be minimum when applied in the direction parallel to the ramp surface as shown in the figure.

The gravitational force action on M is Mg in the downward direction.

For the mass M to be at an equilibrium condition on the ramp, the sum of the total force in any direction will be zero.

Equate the sum of all the forces in the direction parallel to the ramp to zero.

F-Mg\sin\theta=0

\Rightarrow F=Mg \sin\theta

\Rightarrow F=84\times 9.81\sin\theta

\Rightarrow F=824.04\sin\theta N.

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Heat and thermodynamics Numerical ​
soldier1979 [14.2K]

Answer:

K = 227.04 W/m.°C

Explanation:

First we need to find the heat required to melt the ice:

q = m H

where,

q = heat required = ?

m = mass of the ice = 8.5 g = 8.5 x 10⁻³ kg

H = Latent heat of fusion of ice = 3.34 x 10⁵ J/kg

Therefore,

q = (8.5 x 10⁻³ kg)(3.34 x 10⁵ J/kg)

q = 2839 J

Now, we find the heat transfer rate through rod:

Q = q/t

where,

t = time = (10 min)(60 s/1 min) = 600 s

Q = Heat Transfer Rate = ?

Therefore,

Q = 2839 J/600 s

Q = 4.73 W

From Fourier's Law of Heat Conduction:

Q = KA ΔT/L

where,

K = Thermal Conductivity = ?

A = cross sectional area = 1.25 cm² = 1.25 x 10⁻⁴ m²

L = Length of rod = 60 cm = 0.6 m

ΔT = Difference in temperature = 100°C - 0°C = 100°C

Therefore,

4.73 W = K(1.25 X 10⁻⁴ m²)(100°C)/0.6 m

K = (4.73 W)/(0.0208 m.°C)

<u>K = 227.04 W/m.°C</u>

7 0
3 years ago
The difference in arrival times of P and S waves at a seismic observatory can be used to calculate the distance to a quake but n
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Answer:

Direction

Explanation:

The arrival of seismic waves namely P and S wave are essential as it helps in the determination of the distance from the recording seismic station. In order to cover all the possibilities that are related to an earthquake, seismologists draw a circle around the station but this does not help in obtaining the proper information. By the use of two seismic stations, it can draw two circles that intersect at two points, which again does not help in determining the exact epicenter location. So, at least three seismic stations are needed, by which the triangulation method can be implemented, and as the three circles drawn from the three seismic stations intersect at one common point, it represents the exact location of the earthquake epicenter, and the exact direction also is obtained from this.

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3 years ago
What is the magnitude of the acceleration of a speck of clay on the edge of a potter's wheel turning at 45 rpm (revolutions per
Brilliant_brown [7]

Answer:

a_{cp}=7.77m/s^2

Explanation:

The equation for centripetal acceleration is a_{cp}=\frac{v^2}{r}.

We know the wheel turns at 45 rpm, which means 0.75 revolutions per second (dividing by 60), so our frequency is f=0.75Hz, which is the inverse of the period T.

Our velocity is the relation between the distance traveled and the time taken, so is the relation between the circumference C=2\pi r and the period T, then we have:

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Putting all together:

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4 0
3 years ago
A block of mass 15.0 kg slides down a ramp inclined at 28.0∘ above the horizontal. As it slides, a kinetic friction force of 30.
AURORKA [14]

Answer:

Work is done by friction = -165 J

Explanation:

Given:

Mass of block (m) = 15 kg

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Distance (d) = 5.5 m

Find:

Work is done by friction.

Computation:

Work is done by friction = -Fd

Work is done by friction = -(30)(5.5)

Work is done by friction = -165 J

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