Answer:
C. One mole of water was produced from this reaction.
Explanation:
- From the balanced equation:
<em>2H₂ + O₂ → 2H₂O,</em>
It is clear that 2 mol of H₂ react with 1 mol of O₂ to produce 2 mol of H₂O.
- So, if one mole of hydrogen was used in this reaction:
1/2 mol of O₂ was used in the reaction, and
1 mol of water was produced from this reaction.
- So, the correct statement is:
<em>C. One mole of water was produced from this reaction.
</em>
The coefficient is the number in front of the element.
The coefficient is 2
Hope this helps!
Answer:
The correct option is: (D) would function as both an acid and a base
Explanation:
A carbon skeleton bonded to a amino group as well as a carboxyl group, will behave as an acid in basic medium and base in acidic medium. This is because the carboxyl group present in the compound will release a proton in basic medium and the amino group will accept a proton in the acidic medium.
<u>Therefore, a carbon skeleton which is covalently bonded to a carboxyl and amino group will behave as both acid and base.</u>
It is a reaction between an element and a compound that results in a different element and compound
Answer:
By a factor of 12
Explanation:
For the reaction;
A + 2B → products
The rate law is;
rate = k[A]²[B]
As you can see, the rate is proportional to the square of the concentration of A and the of the concentration of B
.
Let's say initially, [A] = x, [B] = y
The rate law in this case is equal to;
rate1 = k. x².y
Now you double the concentration of A and triple the concentration of B.
[A] = 2x, [B] = 3y
The new rate law is given as;
rate2 = k . (2x)². (3y)
rate2 = k . 4x² . 3y
rate2 = 12 k . x² . y
Comparing rate 2 and rate 1, the ratio is given as; rate 2/ rate 1 = 12
Therefore the rate has increased by a factor of 12.