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Ray Of Light [21]
3 years ago
11

Balance the following reaction. C₂H6+ Cl2 C2H4Cl2 + HCI

Chemistry
1 answer:
julsineya [31]3 years ago
8 0

Answer:

C2H6 + 2 Cl2 = C2H4Cl2 + 2 HCl

Explanation:

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C3H8.gas reacts with 5L of O2 at STP
4 0
3 years ago
Good morning, I have a question..
matrenka [14]

Answer:

<h3>The answer is 5.24 mL</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question

mass = 152 g

density = 29 g/cm³

We have

volume =  \frac{152}{29}  \\  = 5.24137931...

We have the final answer as

<h3>5.24 mL</h3>

Hope this helps you

7 0
3 years ago
The reaction for photosynthesis producing glucose sugar and oxygen gas is:
Anvisha [2.4K]

<u><em>1.5 grams of glucose is produced from 2.20 g of CO₂.</em></u>

To find the mass of glucose produced, first you must know the balanced reaction. For this, the Law of Conservation of Matter is followed.

The law of conservation of matter states that since no atom can be created or destroyed in a chemical reaction, the number of atoms that are present in the reagents has to be equal to the number of atoms present in the products.

So, in this case, the balanced reaction is:

6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the amounts of moles of each reactant and product participate in the reaction:

  • CO₂: 6 moles
  • H₂O: 6 moles
  • C₆H₁₂O₆: 1 mole
  • O₂: 6 moles

So, you know that 2.20 g of CO₂ react, whose molar weight is 44.01 g/mole. By definition of molar mass, 1 mole of CO₂ has 44.01 g. So, the number of moles that 2.20 grams of the compound represent is calculated as:

moles of CO_{2} =2.20 grams*\frac{1 mole}{44.01 grams}

moles of CO₂= 0.05 moles

Now you must follow the following rule of three: if by stoichiometry of the reaction 6 moles of CO₂ produce 1 mole of C₆H₁₂O₆, 0.05 moles of CO₂ produce how many moles of C₆H₁₂O₆?

moles of C_{6} H_{12} O_{6} =\frac{0.05moles of CO_{2} *1 mole of C_{6} H_{12} O_{6}}{6moles of CO_{2}}

moles of C₆H₁₂O₆= 8.33*10⁻³

Being the molar mass of glucose 180.18 g/mole, the mass that 8.33*10⁻³ moles of the compound represent is calculated as:

mass of glucose =8.33*10^{-3} moles*\frac{180.18 grams}{1 mole}

<em>mass of glucose= 1.5 grams</em>

Then, <u><em>1.5 grams of glucose is produced from 2.20 g of CO₂.</em></u>

5 0
3 years ago
Name two control substance?
guapka [62]
The two control bases would be water and salt.
6 0
3 years ago
Read 2 more answers
Balance the following Equation Show your work.
7nadin3 [17]

Answer:

1) alr balanced

2) 2 2 1

3) 2 1 1 2

4) 2 3 2

5) 2 1 2 1

6) 1 6 2 3

7) 2 2 1

8) 1 2 1 2

9) 2 5 4 6

10) 3 1 2

3 0
3 years ago
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