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jolli1 [7]
3 years ago
7

What is the molarity (M) of .5 liter of a solution that has 205 g of NaCl dissolved in it?

Chemistry
1 answer:
jeka943 years ago
8 0

Answer:

<h2>Molarity = 7 mol / L</h2>

Explanation:

Since the mass of NaCl and it's volume has been given we can find the molarity by using the formula

<h3>C =  \frac{m}{M \times v}</h3>

where

C is the molarity

m is the mass

M is the molar mass

v is the volume

From the question

v = 0.5 L

m = 205 g

We must first find the molar mass and then substitute the values into the above formula

M( Na) = 23 , M( Cl) = 35.5

Molar mass of NaCl = 23 + 35.5 =

58.5 g/mol

So the molarity of NaCl is

C =  \frac{205}{0.5  \times 58.5}  \\ C =  \frac{205}{29.25}

C = 7.00854

We have the final answer as

<h3>Molarity = 7 mol / L</h3>

Hope this helps you

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As a real gas deviates from ideal gas behavior, the particles _____
Alik [6]

Answer:

Have some attraction towards each other

Explanation:

Gases deviate from the ideal gas behavior because their molecules have forces of attraction between them. At high pressure, the molecules of gases are very close to each other so the molecular interactions start operating and these molecules do not strike the walls of the container with full impact.

Hope this helps :-)

Have a great rest of your day or night!

Enjoy your studies and assignments

<3 simplysun

ps. I do not own any of these answers so please don't give full credit to me

7 0
2 years ago
Name the 3 largest countries in the Middle East
avanturin [10]

ANSWER:

1. Egypt

2. Turkey

3. Iran

Explanation:

7 0
2 years ago
At a certain temperature, 4.0 mol NH3 is introduced into a 2.0 L container, and the NH3 partially dissociates by the reaction. 2
xxMikexx [17]

Answer:

K = 3.37

Explanation:

2 NH₃(g) → N₂(g)  + 3H₂(g)

Initially we have 4 mol of ammonia, and in equilibrium we have 2 moles, so we have to think, that 2 moles have been reacted (4-2).

              2 NH₃(g)    →    N₂(g)  + 3H₂(g)

Initally       4moles             -            -

React        2moles           2m   +   3m

Eq             2 moles          2m        3m

We had produced 2 moles of nitrogen and 3 mol of H₂ (ratio is 2:3)

The expression for K is:  ( [H₂]³ . [N₂] ) / [NH₃]²

We have to divide the concentration /2L, cause we need MOLARITY to calculate K (mol/L)

K = ( (2m/2L) . (3m/2L)³ ) / (2m/2L)²

K = 27/8 / 1 → 3.37

5 0
3 years ago
Read 2 more answers
How many moles are in 117.30 grams of KCLO3?
eduard

0.0081599680129254

Hope this helps?

5 0
2 years ago
g Determine the empirical formula for a compound that contains C, H and O. It contains 40.92% C, 4.58% H, and 54.50% O by mass.
Lady bird [3.3K]

Answer:

The empirical formula for the compound is C3H4O3

Explanation:

The following data were obtained from the question:

Carbon (C) = 40.92%

Hydrogen (H) = 4.58%

Oxygen (O) = 54.50%

The empirical formula for the compound can be obtained as follow:

C = 40.92%

H = 4.58%

O = 54.50%

Divide by their molar mass

C = 40.92/12 = 3.41

H = 4.58/1 = 4.58

O = 54.50/16 = 3.41

Divide by the smallest i.e 3.41

C = 3.41/3.41 = 1

H = 4.58/3.41 = 1.3

O = 3.41/3.41 = 1

Multiply through by 3 to express in whole number

C = 1 x 3 = 3

H = 1.3 x 3 = 4

O = 1 x 3 = 3

The empirical formula for the compound is C3H4O3

6 0
3 years ago
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