D. Same energy level but different sublevel.
<h3>Explanation</h3>
There are four quantum numbers [1]:
- <em>n</em><em>, </em>the principal quantum number,
- <em>l</em>, the orbital angular momentum quantum number,
- <em>
</em>, the magnetic quantum number, and - <em>
</em>, the electron spin quantum number.
As their names might suggest:
- <em>n </em>determines the main energy level of an electron.
- <em>l</em> determines the type of sublevel of an electron.
- Each sublevel might contain more than one orbital. <em></em> gives the orbital of an electron.
- Each orbital contains up to two electrons. <em></em> tells two electrons in the same orbital apart.<em> </em>
The two electrons in question come from the same atom. The question suggests that they have the same <em>n</em>, <em></em>, and <em></em>. As a result, both electrons are in main energy level <em>n</em> = 3. They share the same spin.
However, the two electrons differ in their value of <em>l</em>.
- <em>l </em>= 2 for the first electron. It belongs to a <em>d</em> sublevel.
- <em>l </em>= 1 for the second electron. It belongs to a <em>p</em> sublevel.
<h3>Reference</h3>
[1] Kamenko, Anastasiya, et. al, "Quantum Numbers", Physical & Theoretical Chemistry, Chemistry Libretexts, 24 Mar 2017.
The correct option is B AND C.
An isotope is defined as two or more forms of the same element which contain equal number of protons but different number of neutrons in their nuclei, hence they differ in relative atomic mass but not in chemical properties.
Thus, isotopes has the same number of protons but differ in number of neutrons. Due to this fact, isotopes always have the same atomic number but different mass number. You will notice that the atomic number given for elements B and C are the same [101].
Its C, Outermost Electrons.
Answer:
The rock displaces 475 mL of water.
475 mL is the volume of the rock.
1 mL = 1 cm^3
The mass is just density times volume.
m = 475 * 2.5 = 125 g
Explanation:
Answer:
The concentration would be 0.76 mol/L.
The most common way to solve this problem is to use the formula
c1V1=c2V2
In your problem,
c1 = 4.2 mol/L; V1 = 45.0 mL
c2 = ?; V2 = 250 mL
c2=c1×V1V2 = 4.2 mol/L × 45.0mL250mL = 0.76 mol/L
This makes sense. You are increasing the volume by a factor of about 6, so the concentration should be about ¹/₆ of the original (¹/₆ × 4.2 = 0.7).
Explanation:
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