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8_murik_8 [283]
4 years ago
11

Based on the information given about capsules, which of the following types of molecules would you suspect comprises an S. pneum

oniae capsule? 1. monosaccharide carbohydrate 2. triglyceride lipid 3. polysaccharide carbohydrate 4. disaccharide carbohydrate 5. adenosine triphosphate
Chemistry
1 answer:
Sergio039 [100]4 years ago
8 0

"Polysaccharide carbohydrate" comprises an S. pneumoniae capsule.

<u>Option:</u> C

<u>Explanation:</u>

The lengthy sequences of carbohydrate molecules, primarily polymeric carbohydrates constructed of units of monosaccharides linked together through glycosidic connections, understood as Polysaccharides. This carbohydrate can respond to water by catalyzing amylase enzymes, which generate component sugars.

A major human pathogen is Streptococcus pneumoniae or pneumococcus. The virulence is primarily due to its polysaccharide envelope, which protects it from the recipient immune response, and this has led to comprehensive study of the shell.

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4 0
3 years ago
Bromine (Br2) is produced by reacting HBr with O2, with water as a byproduct. The O2 is part of an air (21 mol % O2, 79 mol % N2
Karolina [17]

Answer:

The mole fractions:

x_{HBr}=\frac{100mol}{318.5}=0.314

x_{Br_2}=\frac{78mol}{318.5}=0.245

x_{H_2O}=\frac{78mol}{318.5}=0.245

x_{O_2}=\frac{62.5mol}{318.5}=0.196

Explanation:

The reaction described is:

2 HBr (g) + 1/2 O_2 (g) \longrightarrow Br_2 (g) + H_2O (g)

The limiting reactant is the HBr (oxygen is in excess).

a) The mass (in moles) balance for this sistem:

n_{Br_2}=\frac{ 1 mol Br_2}{1 mol HBr} *n_{HBr}*0.78

(the 0.78 is because of the fractional conversion)

n_{O_2}=\frac{ 0.5 mol O_2}{1 mol HBr} *n_{HBr}*1.25

(the 1.25 is because of the oxygen excess)

n_{H_2O}=\frac{ 1 mol H_2O}{1 mol Br_2} *n_{Br_2}

There is only one degree of freedom in this sistem, you can either deffine the moles of HBr you have or the moles of Br2 you want to produce. The other variables are all linked by the equations above.

b) Base of calculation 100 mol of HBr:

nn_{HBr}=100 mol HBr

n_{Br_2}=\frac{ 1 mol Br_2}{1 mol HBr} *100mol HBr*0.78

n_{Br_2}=78 mol Br2

n_{O_2}=\frac{ 0.5 mol O_2}{1 mol HBr} *100 mol HBr*1.25

n_{O_2}=62.5 mol O_2

n_{H_2O}=n_{Br_2}= 78 mol

n_{total}=(78+78+100+62.5)mol= 318.5mol

The mole fractions:

x_{HBr}=\frac{100mol}{318.5}=0.314

x_{Br_2}=\frac{78mol}{318.5}=0.245

x_{H_2O}=\frac{78mol}{318.5}=0.245

x_{O_2}=\frac{62.5mol}{318.5}=0.196

4 0
3 years ago
The spontaneous intermingling of atoms among different substances is accomplished by _____.
Mashutka [201]

Answer: The spontaneous intermingling of atoms among different substances is accomplished by diffusion.

Explanation:

Diffusion means to spread out. In diffusion, the molecules or atoms move from a region of high concentration to low concentration.

In other words, we can say that the spontaneous intermingling of atoms among different substances is accomplished by diffusion. Diffusion depends on the random walk of an atom or molecule.

Molecular kinetic energy is the energy of a gas at ordinary temperature in which the atoms or molecules are in rapid motion.

Displacement is the property in which a reactive element displaces less reactive element from its position.

Condensation is the process of changing water vapor into liquid.

Thus, it can be concluded that the spontaneous intermingling of atoms among different substances is accomplished by diffusion.

5 0
3 years ago
Read 2 more answers
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