A dielectric material is inserted between the charged plates of a parallel-plate capacitor. Do the following quantities increase
1 answer:
Answer:
1. Charge on plates (plates remain connected to battery) increases.
2. Electric potential energy (plates isolated from battery before inserting dielectric) decreases.
3.Capacitance (plates isolated from battery before inserting dielectric) increases.
4. Voltage between plates (plates remain connected to battery) remains the same.
5. Charge on plates (plates isolated from battery before inserting dielectric) remains the same.
6. Capacitance (plates remain connected to battery) increases.
7. Electric potential energy (plates remain connected to battery) increases.
8. Voltage between plates (plates isolated from battery before inserting dielectric) decreases.
Explanation:
When a dielectric material is inserted between the plates of a capacitor, the capacitance is increase by a factor K, the dielectric constant.
By the capacitance formula, the other factors change accordingly.
1. Charge on plates (plates remain connected to battery) increases, because charge and capacitance are directly proportional.
2. Electric potential energy (plates isolated from battery before inserting dielectric) decreases, because potential is inversely proportional to capacitance, and potential energy is given by the following formula
3.Capacitance (plates isolated from battery before inserting dielectric) increases.
4. Voltage between plates (plates remain connected to battery) stays the same, because the voltage is applied by the battery.
5. Charge on plates (plates isolated from battery before inserting dielectric) remains constant. If the plates isolated from the battery, then the total charge is conserved.
6. Capacitance (plates remain connected to battery) increases when a dielectric is inserted.
7. Electric potential energy (plates remain connected to battery) increases, because when plates remain connected to battery the voltage remains the same. But the capacitance increases. Therefore, electric potential energy increases.
8. Voltage between plates (plates isolated from battery before inserting dielectric) decreases, because voltage is inversely proportional to capacitance.
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Answer:
a)
b)
Explanation:
a)
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b)
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Answer:
<em>work done in pumping the entire fuel is 466587 J</em>
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Explanation:
weight of the gasoline per volume = 6600 N/m^3
diameter of the tank = 3 m
length of the tank = 2 m
height of the tractor tank above the top of the tank = 5 m
work done in pumping fuel to this height = ?
First, we find the volume of the fuel
since the tank is cylindrical,<em> we assume that the fuel within also takes the cylindrical shape.</em>
<em>Also, we assume that the fuel completely fills the tank.</em>
volume of a cylinder =
where r = radius = diameter ÷ 2 = 3/2 = 1.5 m
volume of the cylinder = 3.142 x x 2 = 14.139 m^3
we then find the total weight of the fuel in Newton
total weight = (weight per volume) x volume
total weight = 6600 x 14.139 = 93317.4 N
work done = (total weight of the fuel) x (height through which the fuel is pumped)
work done in pumping = 93317.4 x 5 = <em>466587 J</em>