Answer:
There is 18.8% lithium by mass in second sample
Explanation:
Both the two samples are pure lithium carbonate. So % lithium by mass will be same in both samples. This can be proved mathematically as follows-
Let's assume weight of first sample is x g
So, 100 g of sample contains 18.8 g of lithium
Hence, x g of sample contains
g of lithium
Now, the second sample has weight equal to 2x g
So, 2x g of sample contains
g of lithium
So, % lithium by mass in second sample =
% = 18.8%
Answer:
1. Classical conditioning. Classical conditioning is a type of associative learning based on the association between a neutral stimulus with another that is significant for a person or an animal in order to generate a similar response.
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Answer:
121.37 moles.
Explanation:
Always one mole of any molecule contains Avogadro number of molecules.
So one mole of methane contains 6.023*10^23 molecules.
Now we need number of moles of methane in 7.31*10^25 molecules.
This is just cross multiplication stuff.
6.023*10^23 molecules —————- 1 mole
7.31*10^25 molecules ——————- ?
= (7.31*10^25) / (6.023*10^23)
= 121.37 moles.
Answer:
Dienes are alkenes that contain two carbon-carbon double bonds, so they have the same properties as these hydrocarbons.
In the attached file are the two reactions of dienes production.
Explanation:
Two ways to obtain dienes are as follows:
-Reaction of oxidative dehydrogenation of an alkane, is an exothermic process and occurs at lower temperatures, diene and water are formed, generating greater conversion at lower temperature levels.
-Dehydration of primary alcohols. The treatment of alcohols with acid at elevated temperatures produces dienes due to water loss. For example, heating ethanol in the presence of sulfuric acid produces ethene by the loss of a water molecule.