Answer:
The concentration of species in 500 mL of a 2.104 M solution of sodium sulfate is 4.208 M sodium ion and 2.104 M sulfate ion. (option E)
Explanation:
Step 1: Data given
Volume = 500 mL = 0.500 L
The concentration sodium sulfate = 2.104 M
Step 2: The equation
Na2SO4 → 2Na+ + SO4^2-
For 1 mol Na2SO4 we have 2 moles sodium ion (Na+) and 1 mol sulfate ion (SO4^2-)
Step 3: Calculate the concentration of the ions
[Na+] = 2*2.104 M = 4.208 M
[SO4^2-] = 1*2.104 M = 2.104 M
The concentration of species in 500 mL of a 2.104 M solution of sodium sulfate is 4.208 M sodium ion and 2.104 M sulfate ion. (option E)
Answer:
I would help but the picture will not load for me :(
Explanation:
Hello,
The answer is titanium because although it is not found unbound to other elements in nature, Titanium is the ninth most abundant element in the Earth's crust
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Answer:
30 protons
Explanation: Each zinc isotope contains 30 protons, 30 massive, positively charged nuclear particles
30 protons, 34 neutrons, and 30 electrons.
The name of the molecule above is <u>Ethene</u>
<h3>What are organic compounds?</h3>
Organic compounds can be defined as compounds containing carbon and hydrogen.
Some classes of organic compounds are:
- Alkanes
- Alkenes
- Alkanols
- Alkanals
- Alkynes
So therefore, he name of the molecule above is Ethene
Learn more about organic compounds:
brainly.com/question/704297
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