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aleksley [76]
3 years ago
11

Two vectors, X and Y, form a right angle. Vector X is 48 inches long and vector Y is 14 inches long. The length of the

Physics
1 answer:
Illusion [34]3 years ago
4 0

Answer:

\left \| \vec R \right \|=50\ inches

Explanation:

<u>Vectors In The Plane</u>

Given two vectors \vec X and \vec Y, their sum is shown as the vector \vec R in the image below. It can be seen the magnitude of R is the hypotenuse of a right triangle. i.e.

\left \| \vec R \right \|=\sqrt{\left \| X \right \|^2+\left \| Y \right \|^2}

The magnitude of \vec X is 48 inches and the magnitude of \vec Y is 14 inches, the magnitude of R is

\left \| \vec R \right \|=\sqrt{48^2+14^2}

\left \| \vec R \right \|=\sqrt{2304+196}=\sqrt{2500}

\left \| \vec R \right \|=50\ inches

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calculate the average acceleration of a car with a starting velocity of 0 m/s that accelerates to 9 m/ s in 3 second
ladessa [460]

Answer:

a = 3 m/s²

Explanation:

a = Δv/t

a = (vf - vi)/t

a = (9 - 0)/3

a = 3m/s²

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3 years ago
What two air masses creates hurricanes?
klio [65]

Answer:

The warm seas create a large humid air mass. The warm air rises and forms a low pressure cell, known as a tropical depression.

Explanation:

Hurricanes arise in the tropical latitudes (between 10 degrees and 25 degrees N) in summer and autumn when sea surface temperature are 28 degrees C (82 degrees F) or higher.

3 0
3 years ago
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A car moves along an x axis through a distance of 980 m, starting at rest (at x = 0) and ending at rest (at x = 980 m). Through
azamat

Answer:

travel time is 32.4 s

maximum speed is 45.36 m/s

Explanation:

given data

distance = 980 m

acceleration = 4.20 m/s² for first 1/4 of that distance

acceleration = -1.40 m/s² for next 3/4 of that distance

to find out

travel time through the 980 m and maximum speed

solution

we know for first 1/4 of that distance is = \frac{980}{4} = 245 m

so  equation of motion

s = ut + 0.5 ×at²     .............1

here u is initial speed = 0 and a is acceleration an t is time

s = ut + 0.5 ×at²

245 = 0+ 0.5 ×4.20 (t)²

t = 10.80 s

so

maximum speed at 1/4 of that distance

use equation of motion

v² - u² = 2as

put here value

v² - 0 = 2(4.20)× (245)

v = 45.36 m/s

so maximum speed is 45.36 m/s

and

for 3/4 distance

use equation of motion

v = u + at

here u is here 45.36 and a is acceleration and t is time and v final speed is 0

0 = 45.36 + (-1.40) × t

t = 32.4 s

so travel time is 32.4 s

4 0
3 years ago
Describe factors than can make dishes in restaurants have variable nutritional values
Pavlova-9 [17]
Hello

Overheating food This factor can decrease the number of nutrients in a food, making it less housing different amounts of ingredients than what is called for in the recipe; overcooking, which can reduce the vitamin content; substituting cooking oils, which can add or reduce the amount of calories and fat; and adjusting portion sizes, which may make them too large or too small.althy for eating.
HAve a nice day
5 0
3 years ago
Oh football player kicks a football from the height of 4 feet with an initial vertical velocity of 64 ft./s use the vertical mot
Stolb23 [73]

Answer:

4.1 seconds

Explanation:

The height of the football is given by the equation:

H = -16t^2 + V*t + S

Using the inicial position S = 4 and the inicial velocity V = 64, we can find the time when the football hits the ground (H = 0):

0 = -16t^2 + 64*t + 4

4t^2 - 16t - 1 = 0

Using Bhaskara's formula, we have:

\Delta = b^2 - 4ac = (-16)^2 - 4*4*(-1) = 272

t_1 = (-b + \sqrt{\Delta})/2a

t_1 = (16 + 16.49)/8 = 4.06\ seconds

t_2 = (-b - \sqrt{\Delta})/2a

t_2 = (16 - 16.49)/8 = -0.06\ seconds

A negative time is not a valid result for this problem, so the amount of time the football is in the air before hitting the ground is 4.1 seconds.

7 0
3 years ago
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