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Zepler [3.9K]
3 years ago
8

What is the acceleration of a car initially traveling at -5m/s and reaching -22m/s in 3s.

Physics
1 answer:
lozanna [386]3 years ago
4 0

Answer:

a=-5.67\ m/s^2

Explanation:

Given that,

Initial velocity, u = -5 m/s

Final velocity, v = -22 m/s

Time, t = 3s

We need to find the acceleration of the car. The formula of it is given by :

Acceleration,

a=\dfrac{v-u}{t}\\\\a=\dfrac{(-22)-(-5)}{3}\\\\a=-5.67\ m/s^2

So, the acceleration of the car is -5.67\ m/s^2.

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Explanation:

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Red light of wavelength 630 nm passes through two slits and then onto a screen that is 1.4 m from the slits. The center of the 3
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Answer:

Part a)

f = 4.76 \times 10^{14} Hz

Part b)

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Part c)

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Explanation:

Part a)

As we know that the speed of light is given as

c = 3 \times 10^8 m/s

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now the frequency of the light is given as

f = \frac{c}{\lambda}

so we have

f = \frac{3 \times 10^8}{630 \times 10^{-9}}

f = 4.76 \times 10^{14} Hz

Part b)

Position of Nth maximum intensity on the screen is given as

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so here we know for 3rd order maximum intensity

y_3 = 0.76 cm

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0.76 \times 10^{-2} = \frac{3(630 \times 10^{-9})(1.4)}{d}

d = 3.48 \times 10^{-4} m

Part c)

angle of third order maximum is given as

d sin\theta = 3 \lambda

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\theta = 0.311 degree

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Explanation:

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