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liberstina [14]
3 years ago
14

Comets travel around the sun in elliptical orbits with large eccentricities. If a comet has speed 1.6×104 m/s when at a distance

of 2.7×1011 m from the center of the sun, what is its speed when at a distance of 4.8×1010 m?
Physics
1 answer:
xz_007 [3.2K]3 years ago
3 0

Answer:

v₂ = 7.6 x 10⁴ m/s

Explanation:

given,

speed of comet(v₁) = 1.6 x 10⁴ m/s

distance (d₁)= 2.7 x 10¹¹ m

to find the speed when he is at distance of(d₂) 4.8 × 10¹⁰ m

v₂ = ?

speed of planet can be determine using conservation of energy

K.E₁ + P.E₁ = K.E₂ + P.E₂

\dfrac{1}{2}mv_1^2-\dfrac{GMm}{r_1} = \dfrac{1}{2}mv_2^2-\dfrac{GMm}{r_2}

\dfrac{1}{2}v_1^2-\dfrac{GM}{r_1} = \dfrac{1}{2}v_2^2-\dfrac{GM}{r_2}

v_2^2= v_1^2 + \dfrac{2GM}{r_2}-\dfrac{2GM}{r_1}

v_2= \sqrt{v_1^2 +2GM(\dfrac{1}{r_2}-\dfrac{1}{r_1})}

v_2= \sqrt{(1.6\times 10^4)^2 +2\times 6.67 \times 10^{-11}\times 1.99 \times 10^{30}(\dfrac{1}{4.8\times 10^{10}}-\dfrac{1}{2.7\times 10^{11}})}

v₂ = 7.6 x 10⁴ m/s

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You need to repair a gate on the farm. The gate weighs 100 kg and pivots as indicated. A small diagonal bar supports the gate an
tekilochka [14]

Answer:

The force is  F = 3920 \ N

Explanation:

The diagram for this question is shown on the first uploaded image

   From the question we are told that

          The weight of the gate is G  =  100\  kg

 

The vertical component of F is  F_y =  F\ sin  \theta

   From the diagram , taking moment about the pivot we have  

                W_g  * 2 - F_y  * 1 =  0

Where W_g  is the weight of the gate evaluated as

             W_g  =  m_g * g =  100 * 9.8 =  980 \ N

=>        980 * 2 - Fsin(30)  * 1 =  0

=>         F = \frac{1960}{sin(30)}

=>      F = 3920 \ N

7 0
3 years ago
A merry-go-round of radius 2 m is rotating at one revolution every 5 s. A
galben [10]

Answer:

a) The angular speed of the child is approximately 1.257 rad/s

b) The angular speed of the teenager is approximately 1.257 rad/s

c) The tangential speed of the child is approximately 1.257 m/s

d) For the child, r = 2 m

The tangential speed of the teenager is approximately 2.513 m/s

Explanation:

The revolutions per minute, r.p.m. of the merry-go-round = 1 revolution/(5 s)

The radius of the merry-go-round = 2 m

The location of the child = 1 m from the axis

The location of the teenager = 2 m from the axis

1 revolution = 2·π radians

Therefore, we have;

The angular speed, ω = (Angle turned)/(Time elapsed) = (2·π radians)/(5 s)

∴ The angular speed of the merry-go-round, ω = 2·π/5 radians/second

a) The angular speed of the child = The angular speed of the merry-go-round = 2·π/5 radians/second ≈ 1.257 rad/s

b) The angular speed of the teenager = The angular speed of the merry-go-round = 2·π/5 radians/second ≈ 1.257 rad/s

c) The tangential speed, v = r × The angular speed, ω

Where;

r = The radius of rotation of the object

For the child, r = 1 m

The tangential speed of the child = 1 m × 2·π/5 radians/second = 2·π/5 m/s ≈ 1.257 m/s

d) For the child, r = 2 m

The tangential speed of the teenager = 2 m × 2·π/5 radians/second = 4·π/5 m/s ≈ 2.513 m/s

8 0
2 years ago
If the 80 ohm resistor fails, will the 50 ohm and 100 ohm resistor continue to operate? Why or why not?
sleet_krkn [62]

Answer:

No, the 50 ohm and 100 ohm resistor will not continue to operate.

Explanation:

A closed circuit is the circuit in which there is no break between the negative and the positive end of the battery.

When in this, combinational circuit the 80 ohm resistor fail then there will not any continue supply of current in the circuit due to the breakage because the electron will flow from negative end of the battery to positive end if their is no breaking in the circuit.

Therefore the 50 ohm and 100 ohm circuit will not continue to operate because of the breaking of the circuit and current will not flow.

7 0
3 years ago
A wave with a frequency of 17 Hz has a wavelength of 4 meters. At what speed (in m/s) will this wave travel?
Molodets [167]

Answer:68m/s

Explanation:

Frequency=17Hz

Wavelength=4metre

Wave speed=frequency x wavelength

Wave speed =17 x 4

Wave speed =68m/s

5 0
3 years ago
A train takes 2h to reach station B from station A and 3h to return back to A.The distance between the station is 200km, then it
serg [7]

Answer:

80km/hr

Explanation:

Total distance: 400km

Total time 5 hours

Average speed= distance/time

400/5= 80km/hr

8 0
3 years ago
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