Divide 180kg and 90m3 and your density will be 2kg/m3
Answer:
The partial pressure of nitrogen is 597.5 torr
Explanation:
Step 1: Data given
Mol fraction of N = 0.781
Mol fraction of O = 0.209
Mol fraction Ar = 0.010
Atmospheric pressure = 765.0 torr
The partial pressure is given by Pi = Xi * Pt
⇒ χ
i = the mole fraction of gas i in the mixture
⇒ P
total = the total pressure of the mixture
Step 2: Calculate the partial pressure of nitrogen
P(N) = mol fraction of N * atmospheric pressure
P(N) = 0.781 * 765.0 torr = 597.5 torr
The partial pressure of nitrogen is 597.5 torr
262. 5cm3.
using the Boyles law formula. p1v1=p2v2
P1=760torr.
v1=525cm³
p2=760×2=1520torr.
v2=?
p1v1=p2v2
760×525=1520×v2
v2=[ 760×525]÷1520
v2= 262.5cm³
when the pressure increases, the volume decreases.