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Liono4ka [1.6K]
2 years ago
12

Which of these boxes will not accelerate?

Chemistry
1 answer:
love history [14]2 years ago
3 0

Answer:

B as all the forces cancel out

Explanation:

20-20=0

25-25=0

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There are 55.0 g of neon gas in a 3.0 L cylinder, the pressure is 4.5 atm what is the temp of the gas
marshall27 [118]

Answer:

60.9 Kelvin

Explanation: First, write out everything that you know. You are tring to find the temperature, so the temperature will be represented by x.

Pressure (P)= 4.5 atm

Volume (V)= 3L

Number of Moles (n)= ?

Gas Consant (R)= 0.0821, if the pressure is in atm, that means r is 0.0821

Temperature (T)= x

We don't have all the information we need to plug the values into the equation. We still need to know how many moles 55.0 grans of neon is.

Ne in Grams= 55

Atomic Mass of Ne= 20.1797

55/20.1797= 2.7  

moles= 2.7

Now that we have all the information we need, plug everying into the equation. In case you don't know, the Ideal Gas Law Equation is PV= nRT.

(4.5)(3) = (2.7)(0.821)x    

x= 60.9

Now you have your temperature! It is 60.9 in Kelvin.

4 0
3 years ago
Someone plz help me !!<br><br> Science <br> Or<br> Bias?
Artist 52 [7]
1st one is Science and the 2nd one is Bias
8 0
3 years ago
How many Liters of space will a 70.0g sample of CO2 occupy?
Tanzania [10]

Answer:

  35.6 liters at STP

Explanation:

The molar mass of carbon dioxide is about 44.01 g/mol. The volume of a mole of ideal gas at STP is 22.4 L, so the volume of 70.0 g will be ...

  (70.0g)/(44.01 g/mol)·(22.4 L/mol) ≈ 35.6 L

5 0
3 years ago
If you dilute 19.0 mL of the stock solution to a final volume of 0.310 L , what will be the concentration of the diluted solutio
Dahasolnce [82]

Answer:

M_2=0.613M_1

Explanation:

M_1 = Concentration of stock solution

M_2 = Concentration of solution

V_1 = Volume of stock solution = 19 mL

V_2 = Volume of solution = 0.31 L= 310 mL

We have the relation

M_1V_1=M_2V_2\\\Rightarrow M_2=\dfrac{M_1V_1}{V_2}\\\Rightarrow M_2=\dfrac{M_119}{310}\\\Rightarrow M_2=M_1\times\dfrac{19}{310}\\\Rightarrow M_2=0.613M_1

\boldsymbol{\therefore M_2=0.613M_1}

The concentration of the diluted solution will be 0.613 times the concentration of the stock solution.

6 0
3 years ago
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Varvara68 [4.7K]

Answer:

dolo HAHAHAAHAHHAHAHAHA

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