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VARVARA [1.3K]
3 years ago
15

When you drive a car around a curve that is not banked, what force provides the centripetal acceleration? HINT: Think about turn

ing a curve on ice. If the curve is banked, what additional force plays a role in providing the centripetal force? Draw force diagrams to clarify your thinking.

Physics
2 answers:
Fittoniya [83]3 years ago
4 0

Explanation:

When you drive a car around a curve that is not banked, the frictional force between the tyres of the car and the road provides the centripetal acceleration and the centripetal force. Figure A shows the force acting on the object in unbanked road.

Figure B shows the banked curve. In this type of curve, the horizontal component of the normal force is balanced by the centripetal force as well as centripetal acceleration.

algol [13]3 years ago
3 0
The centripetal force is provided by the friction between the tyres and the ground. That's why a car will slip on ice, because there is less friction.
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Relative to the positive horizontal axis, rope 1 makes an angle of 90 + 20 = 110 degrees, while rope 2 makes an angle of 90 - 30 = 60 degrees.

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\sin(60^\circ) \bigg(R_1 \cos(110^\circ) + R_2 \cos(60^\circ)\bigg) - \cos(60^\circ) \bigg(R_1 \sin(110^\circ) + R_2 \sin(60^\circ)\bigg) = 0\sin(60^\circ) - mg\cos(60^\circ)

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