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VARVARA [1.3K]
3 years ago
15

When you drive a car around a curve that is not banked, what force provides the centripetal acceleration? HINT: Think about turn

ing a curve on ice. If the curve is banked, what additional force plays a role in providing the centripetal force? Draw force diagrams to clarify your thinking.

Physics
2 answers:
Fittoniya [83]3 years ago
4 0

Explanation:

When you drive a car around a curve that is not banked, the frictional force between the tyres of the car and the road provides the centripetal acceleration and the centripetal force. Figure A shows the force acting on the object in unbanked road.

Figure B shows the banked curve. In this type of curve, the horizontal component of the normal force is balanced by the centripetal force as well as centripetal acceleration.

algol [13]3 years ago
3 0
The centripetal force is provided by the friction between the tyres and the ground. That's why a car will slip on ice, because there is less friction.
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Which object will have greater acceleration? Why?​
dexar [7]

Answer:

Object D

Explanation:

Use Newton's Second Law to determine the acceleration that each object has.

  • F = ma

The force applied in both cases is 50 N, but the mass for object C and object D is different.

Let's start with object C first:

  • F = ma
  • 50 N = 10 kg · a
  • 50 = 10a
  • 5 = a

The acceleration object C undergoes is 5 m/s².  

Now let's calculate object D next:

  • F = ma
  • 50 N = 2 kg * a
  • 50 = 2a
  • 25 = a

The acceleration object D undergoes is 25 m/s².

Object D has greater acceleration because it has a smaller mass. The object with a smaller mass will accelerate more in order to satisfy Newton's 2nd Law.

7 0
3 years ago
What is Initial temperature and final temperature equations??<br> ...?
Neporo4naja [7]
One that can help you is:
ΔT=<span>T<span>Final</span></span>−<span>T<span>Initia<span>l
That is of course adding both tmepratures. There is one more that is a lil bit more complex 
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8 0
3 years ago
The space shuttle travels at a speed of about 7.6times10^3 m/s. The blink of an astronaut's eye lasts about 110 ms. How many foo
sveta [45]

Answer:

It covers distance of 9.15 football fields in the said time.

Explanation:

We know that

Distance=Speed\times Time

Thus distance covered in blinking of eye =

Distance=7.6\times 10^{3}m/s\times 110\times 10^{-3}s\\\\Distance=836 meters

Thus no of football fields=\frac{936}{91.4}=9.15Fields

7 0
3 years ago
If an electric current of 8.50 A flows for 3.75 hours through an electrolytic cell containing copper-sulfate (CuSO4) solution, t
muminat

Answer:

75.5g

Explanation:

From the ionic equation, we can write

CU^{2+}+SO^{2-}_{4}\\

next we find the number of charge

Note Q=it

for i=8.5A, t=3.75 to secs 3.75*60*60=13500secs

hence

Q=8.5*13500\\Q=114750C

Since one faraday represent one mole of electron which equal 96500C

Hence the number of mole produced by 114750C is

114750/96500=1.2mol

The mass of copper produced is

mol=\frac{mass}{molar mass} \\mass=mole*molar mass\\mass=1.2*63.5\\mass=75.5g

Hence the amount of copper produced is 75.5g

7 0
3 years ago
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