1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
VARVARA [1.3K]
3 years ago
15

When you drive a car around a curve that is not banked, what force provides the centripetal acceleration? HINT: Think about turn

ing a curve on ice. If the curve is banked, what additional force plays a role in providing the centripetal force? Draw force diagrams to clarify your thinking.

Physics
2 answers:
Fittoniya [83]3 years ago
4 0

Explanation:

When you drive a car around a curve that is not banked, the frictional force between the tyres of the car and the road provides the centripetal acceleration and the centripetal force. Figure A shows the force acting on the object in unbanked road.

Figure B shows the banked curve. In this type of curve, the horizontal component of the normal force is balanced by the centripetal force as well as centripetal acceleration.

algol [13]3 years ago
3 0
The centripetal force is provided by the friction between the tyres and the ground. That's why a car will slip on ice, because there is less friction.
You might be interested in
Two particles with oppositely signed charges are held a fixed distance apart. The charges are equal in magnitude and they exert
damaskus [11]

Answer:

the force will decrease to 3/4 of its original value.

Explanation:

The initial electric force between the two charges is:

F = k \frac{q\cdot q}{r^2}

where

k is the Coulomb's constant

q is the magnitude of each charge

r is their separation

Later, half of one charge is transferred to the other charge; this means that one charge will have a charge of

q+\frac{q}{2}=\frac{3}{2}q

while the other charge will be

q-\frac{q}{2}=\frac{q}{2}

So, the new force will be

F' = k \frac{(\frac{q}{2})\cdot (\frac{3}{2}q)}{r^2}=\frac{3}{4} (k\frac{q\cdot q}{r^2})=\frac{3}{4}F

So, the force will decrease to 3/4 of its original value.

6 0
3 years ago
An applied force of 50 N is used to accelerate an object, that weighs 73 N, to the right across a frictional surface. The object
Hunter-Best [27]

Answer:

5.38 m/s^2

Explanation:

NET force causing the object to accelerate  =  50 -10 = 40 N

Mass of the object =  73 N / 9.81 m/s^2 = 7.44 kg

F = ma

40 = 7.44 * a         a = 5.38 m/s^2

6 0
2 years ago
Julio hit a baseball. What caused the ball to change direction at the time of impact?
WARRIOR [948]
The answer is c. the force of his swing

At the time of the impact, there is a collision between two bodies moving in opposite directions. 

The force exerted on the ball causes the change of velocity.
7 0
3 years ago
Read 2 more answers
Types of mechanical waves include
USPshnik [31]
I think surface waves
4 0
3 years ago
What do astronomers use in addition to parallax to find the actual distance of stars that are close to Earth?
IgorLugansk [536]

Answer:

trigonometry (guessing)

Explanation:

ellipse: is the shape of an orbit : looks like an oval

periapsis : shortest distance between something like the moon and the planet its orbiting around like the earth

parallax is triangulation. like how gps works. looking at a star one day and then looking at it again 6 months later, an astronomer can see a difference in the viewing angle for the star. With trigonometry, the different angles yield a distance. This technique works for stars within about 400 light years of earth

https://science.howstuffworks.com/question224.htm

By comparing the intrinsic brightness to the star's apparent brightness we can calculate the distance of stars

1/r^2 rule states that the apparent brightness of a light source is proportional to the square of its distance.Jan 11, 2022

https://www.space.com/30417-parallax.html

alternative distance measurement for stars used by most astronomers is the parsec. A star with a parallax angle of 1 arcsecond has a distance of 1 parsec, or 1 parsec per arcsecond of parallax, which is about 3.26 light years

blossoms.mit.edu

.

7 0
2 years ago
Other questions:
  • HELP PLEASE!!!
    12·1 answer
  • Calculate how much work you need to move the 130 N trunk to a ledge 2 m above.
    10·2 answers
  • What is the percentage increase IN kinetic energy(K.E) ,If the momentum(p) of a moving body is increase by 10%?And How? (If K.E=
    15·1 answer
  • Do i become a professional astrophysicist after getting PhD in Astrophysics ? Or will i be a postdoc research student i mean wil
    14·1 answer
  • A person desires to reach a point that is 2.17 km from her present location and in a direction that is 29.6° north of east. Howe
    15·1 answer
  • Energy is released during the fission of pu-239 atoms as a result of the
    14·1 answer
  • 40 POINTS!!! + BRAINLIEST!!!
    11·1 answer
  • Difference Between Newton's first law and third law of motion​
    5·2 answers
  • Drag each tile to the correct box a chemical reaction takes place in which energy is released arrange the reactions characterist
    8·1 answer
  • An object is thrown upward with initial velocity of 30m/s at angle of 30 degree to the horizontal. calculate the components of t
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!