When you drive a car around a curve that is not banked, what force provides the centripetal acceleration? HINT: Think about turn
ing a curve on ice. If the curve is banked, what additional force plays a role in providing the centripetal force? Draw force diagrams to clarify your thinking.
2 answers:
Explanation:
When you drive a car around a curve that is not banked, the frictional force between the tyres of the car and the road provides the centripetal acceleration and the centripetal force. Figure A shows the force acting on the object in unbanked road.
Figure B shows the banked curve. In this type of curve, the horizontal component of the normal force is balanced by the centripetal force as well as centripetal acceleration.
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Answer:
Ep = 3924 [J]
Explanation:
To calculate this value we must use the definition of potential energy which tells us that it is the product of mass by the acceleration of gravity by height.
where:
Ep = potential energy [J] (units of Joules)
m = mass = 40 [kg]
g = gravity acceleration = 9.81 [m/s²]
h = elevation = 10 [m]
<h3>Hi there !</h3><h2>Option A is correct </h2><h3> Please refer the attachment for explanation</h3><h2>Stay safe, stay healthy and blessed</h2><h2>Have a marvelous day</h2><h2>Thank you</h2>
