When you drive a car around a curve that is not banked, what force provides the centripetal acceleration? HINT: Think about turn
ing a curve on ice. If the curve is banked, what additional force plays a role in providing the centripetal force? Draw force diagrams to clarify your thinking.
2 answers:
Explanation:
When you drive a car around a curve that is not banked, the frictional force between the tyres of the car and the road provides the centripetal acceleration and the centripetal force. Figure A shows the force acting on the object in unbanked road.
Figure B shows the banked curve. In this type of curve, the horizontal component of the normal force is balanced by the centripetal force as well as centripetal acceleration.
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At t=0, the particle was at its equilibrium position. The time period is 32 seconds, so in 8 seconds, it will reach the extreme location once, and hence, in 8 seconds, it will cover a distance equivalent to its amplitude.
Answer:
0.73 W/m²
0.2522 W/m²
Explanation:
= Unpolarized light = 1.46 W/m²
= Analyzer angle = 54°
Light through first filter
The intensity of the light leaving the polarizer is 0.73 W/m²
After passing through analyzer
The intensity of the light that reaches the photocell is 0.2522 W/m²
As per Weins displacement law the wavelength of light for which we get the peak of the graph is always inversely proportional to the temperature.
So we can say
So here if temperature becomes more cool then wavelength will increase
here we know that
It means the hottest star out of all three is star 3
and coolest star is star 1
now if we star 2 becomes cooler then it means its temperature will go near to star 1 and hence it will more look like to star 1.
So correct answer is
it will look more like Star 1