Answer:
r(b) = 2.45r
Explanation:
Parameters given:
Satellite A
Mass = m
Orbit radius = r
Satellite B
Mass = 6m
Orbit radius = r(b)
Gravitational force between Earth and Satellite A, F(A) is:
F(A) = (G*M*m)/r²
F(A) = GMm/r²
Gravitational force between Earth and Satellite B, F(B) is:
F(B) = (G*M*6m)/r(b)²
F(B) = 6GMm/r(b)²
Since F(A) = F(B),
GMm/r² = 6GMm/r(b)²
=> r(b)² = 6r²
r(b) = 2.45r
Answer:
C. Newton
Explanation:
Definition of newton: The SI unit of force. It is equal to the force that would give a mass of one kilogram an acceleration of one meter per second per second, and is equivalent to 100,000 dynes.
Hope this helped : )
Answer:
Using
Period ( P) is given as
P~√(L/g).
a) since mass has no effect on the period of a pendulum. So, the period will remain 1.8seconds
b) using the formula above ,period varies with the square root of the length. Thus , when the length doubles, the period is multiplied by √2. So, the period is 1.8s*√2 = 2.54s
c) in this case, the period is multiplied by √(1/2).
1.8√(1/2)=1.27s.
d) amplitude of the pendulum doesn't affect the period (unless itsvery high, so, the period is still 1.8s