All categories

3 years ago

I really need this answer sombody please help fast Please help fast !!

Physics

1 answer:

Reil [10]3 years ago

6 0

Matter is a lot like energy.

<em>It can't be created or destroyed</em>. It can only be moved around, shifted, rearranged, transformed, disguised, etc. Never created or destroyed.

If you suddenly see some matter that wasn't there a moment ago, it had to come from somewhere. It couldn't just appear out of nothing.

If you suddenly STOP seeing some matter that was there a moment ago, it had to go somewhere. It couldn't just disappear into nothing.

You might be interested in

The human activities in two locations are described below:

Bogdan [553]

Air pollution level is higher in Location B, because poisonous fumes are produced when coal burns.

5 0

3 years ago

Read 2 more answers

The process by which metamorphic rock changes to igneous rock begins with?

Strike441 [17]

Melting, as igneous rock is magma or lava that has cooled and hardened.

5 0

3 years ago

Use the values from PRACTICE IT to help you work this exercise. Suppose the same two vehicles are both traveling eastward, the c

Mariulka [41]

Answer:

A. $v_{3}=12.17m/s$

B. $v_{car}=6.3m/s\\v_{truck}=-6.3m/s$

C. ΔK $=-4.13x10^3J$

Explanation:

From the exercise we know that the car and the truck are traveling eastward. I'm going to name the car 1 and the truck 2

$v_{1}=5.79m/s\\m_{1}=102kg\\v_{2}=18.5m/s\\m_{2}=103kg$

A. Since the two vehicles become entangled the final mass is:

$m_{3}=102kg+103kg=205kg$

From linear momentum we got that:

$p_{1}=p_{2}$

$m_{1}v_{1}+m_{2}v_{2}=m_{3}v_{3}$

$v_{3}=\frac{m_{1}v_{1}+m_{2}v_{2}}{m_{3} }=\frac{(102kg)(5.79m/s)+(103kg)(18.5m/s)}{(205kg)}$

$v_{3}=12.17m/s$

B. The change in velocity of both vehicles are:

For the car

$v_{car}=v_{f}-v_{o}=12.17m/s-5.79m/s=6.38m/s$

For the truck

$v_{truck}=12.17m/s-18.5m/s=-6.3m/s$

C. The change in kinetic energy is:

ΔK= $K_{2}-K_{1} =\frac{1}{2}m_{3}v_{3}^{2}-(\frac{1}{2}m_{1}v_{1}^{2}+\frac{1}{2}m_{2}v_{2}^{2})$

ΔK= $\frac{1}{2}(205)(12.17)^{2}-(\frac{1}{2}(102)(5.79)^{2}+\frac{1}{2}(103)(18.5)^{2})=-4.13x10^{3}J$

ΔK $=-4.13x10^{3}J$

6 0

3 years ago

El movimiento de los cuerpos y la formación de imágenes son ejemplos de esta clase de fenómeno

77julia77 [94]

Answer:

depende de que fenómenos nos referimos de acuerdo al los cuerpos de formación puede aver movimiento contante

7 0

3 years ago

The colour of star depend on its temperature, why?

taurus [48]

<em>Another key factor that determines a star's colour is its temperature. As stars become hotter, the overall radiated energy increases, and the peak of the curve changes to shorter wavelengths. To put it another way, when a star heats up, the light it produces moves toward the blue end of the spectrum.</em>

4 0

3 years ago