Force = 9x10^9 x (6x10^-7 x 6x 10^-7) / (.5)^2
= 0.013 N
Using the formula;
F = 9x10^9 x (Q1 x Q2) / r^2
Answer:
0.2
Explanation:
Horizontal force=100N
Weight of crate=500 N
We have to find the coefficient of kinetic friction.
Normal ,N=Weight=500N
Horizontal force,
Where
=Horizontal force
N=Normal force
=Coefficient of kinetic friction
Substitute the values in the formula


Hence, the coefficient of kinetic friction =0.2
Ok so it is 42.8 because if you - 43.9 by 1.1 by the way don’t listen to any of the I just want point
Answer
given,
flow from the artery = 3.5 x 10⁻⁶ m³/s
Radius of artery = 5.80 x 10⁻³m
area = π R²
= π x (5.8 x 10⁻³)²
= 1.06 x 10⁻⁴ m²


v = 0.033 m/s
b) new velocity of flow
Radius = R' = R/4
A V = A' V'
R² V = R'² V'
R^2 V = (\dfrac{R}{4})^2 V'
V' = 16 V
V' = 16 x 0.033
V' =0.528 m/s
Answer:
I dont get what your asking. If u explaint to me what your asking ill tell you the answer in the comments.
Explanation: