Hi ;-)
1 hour ⇒ 105 km
0,5 hour (30 minutes) ⇒ 105 km : 2 = 52,5 km
3 hours 30 minutes ⇒ 3 · 105 km + 52,5 km =
= 315 km + 52,5 km = <u>367,5 km</u>
The peak radiation will occur at 97 nm.
Answer:
b = 5.164 m is the minimum thickness of the dam
Explanation:
Given
SG = 5
h = 20 m
b = ?
w = 1 m
γw = 9800 N/m³
We can get the forces as follows
Fp = γw*(h/2)*(h*w)
⇒ Fp = (9800 N/m³)*(20 m/2)*(20 m*1 m) = 1.96*10⁶N
W = (SG*γw)*(h*b*w)
⇒ W = (5*9800 N/m³)*(20 m*b*1 m) = (9.8*10⁵N/m)*b
Then, we apply
∑M₀ = 0 (counterclockwise)
- Fp*(h/3) + W*(b/2) = 0
⇒ - 1.96*10⁶N*(20 m/3) + (9.8*10⁵N/m)*b*(b/2) = 0
- 13.066*10⁶N-m + (4.9*10⁵N/m)*b² = 0
⇒ b = 5.164 m is the minimum thickness of the dam
Answer:
lol do you still need help?
Explanation:
Answer:
The height is : 60.025 m
Explanation:
The flowerpot falls off the balcony with zero launch angle
Given the time of fright as 3.5 s then ;
The formula to apply is ;
3.5²= 2H/9.8
12.25 =2H/9.8
12.25 * 9.8 = 2H
120.05 = 2H
120.05/2 = H
60.025 =H
