Answer:
(d) 2 pF
Explanation: the charge on capacitor is given by the expression
Q=CV
where Q=charge
C=capacitance
V=voltage across the plate of the capacitor
here we have given Q=500 pF, V=250 volt
using this formula C=![\frac{Q}{V}](https://tex.z-dn.net/?f=%5Cfrac%7BQ%7D%7BV%7D)
=500×
×![\frac{1}{250}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B250%7D)
=2×![10^{-12}](https://tex.z-dn.net/?f=10%5E%7B-12%7D)
=2 pF
Answer:
P > 142.5 N (→)
the motion sliding
Explanation:
Given
W = 959 N
μs = 0.3
If we apply
∑ Fy = 0 (+↑)
Ay + By = W
If Ay = By
2*By = W
By = W / 2
By = 950 N / 2
By = 475 N (↑)
Then we can get F (the force of friction) as follows
F = μs*N = μs*By
F = 0.3*475 N
F = 142.5 N (←)
we can apply
P - F > 0
P > 142.5 N (→)
the motion sliding
Answer:
instances of hazardous practices are not utilizing headlights appropriately, driving unreasonably quick for conditions, closely following, dangerous passing, or path evolving, and so on. Inability to wear a safety belt is a high-chance conduct that frequently makes the results of an impact more terrible.
Explanation:
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