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zhenek [66]
3 years ago
14

A steam power plant is represented as a heat engine operating between two thermal reservoirs at 800 K and 300 K. The temperature

of the steam in the boiler is 550 K and the temperature of the saturated water in the condenser is 330 K. The rates of heat transfer in the boiler and condenser are 4 MW and 2 MW, respectively. Please answer the following.
Required:
a. Represent the devices present in the heat engine and include their name along with the data given in the problem.
b. If this steam power plant were to operate as a reversible heat engine, with the boiler and condenser temperatures, what would be its thermal efficiency?
c. Use your result from part (b) to determine if the actual steam power plant can achieve such thermal efficiency. Justify your answer.
d. For the actual steam power plant is the Clausius inequality satisfied? Show you computation and discuss whether your result agrees or disagrees with your answer in part (c).
Engineering
1 answer:
Sergeeva-Olga [200]3 years ago
4 0
Yeet is the answer .....
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26 V is measured across a 220 Ω resistance. This means that resistor current equals ________. Group of answer choices 1.2 A 57 A
zysi [14]
You can use ohm’s law
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Since the engineering design process may take the engineer back to its beginning, the process is considered ________
Valentin [98]

Answer:

Cyclical

Explanation:

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7 0
3 years ago
1. Assume that EAX contains ff ff ff 51 and the doubleword referenced by value contains ff ff ff f1.
IRINA_888 [86]

Answer:

1. True

2. False

Explanation:

given data

EAX contains =  ff ff ff 51

doubleword referenced = ff ff ff f1

conditional jump add = eax

solution

1st statement is true

but 2nd statement is false

as here

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6 0
4 years ago
This is just so I can flip the picture
Pepsi [2]

Answer:

ok

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7 0
4 years ago
A steel wire is suspended vertically from its upper end. The wire is 400 ft long and has a diameter of 3/16 in. The unit weight
jek_recluse [69]

Answer:

a) the maximum tensile stress due to the weight of the wire is 1361.23 psi

b) the maximum load P that could be supported at the lower end of the wire is 624.83 lb

Explanation:

Given the data in the question;

Length of wire L = 400 ft = ( 400 × 12 )in = 4800 in

Diameter d = 3/16 in

Unit weight w = 490 pcf

First we determine the area of the wire;

A = π/4 × d²

we substitute

A = π/4 × (3/16)²

A = 0.0276 in²

Next we get the Volume

V = Area × Length of wire

we substitute

V = 0.0276 × 4800

V = 132.48 in³

Weight of the steel wire will be;

W = Unit weight × Volume

we substitute

W = 490 × ( 132.48 / 12³ )

W = 490 × 0.076666

W = 37.57 lb

a) the maximum tensile stress due to the weight of the wire;

σ_w = W / A

we substitute

σ_w = 37.57 / 0.0276

= 1361.23 psi

Therefore, the maximum tensile stress due to the weight of the wire is 1361.23 psi

b) the maximum load P that could be supported at the lower end of the wire. Allowable tensile stress is 24,000 psi

Maximum load P that the wire can safely support its lower end will be;

P = ( σ_{all - σ_w )A

we substitute

P = ( 24000 - 1361.23  )0.0276

P = 22638.77 × 0.0276

P = 624.83 lb

Therefore, the maximum load P that could be supported at the lower end of the wire is 624.83 lb

5 0
3 years ago
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