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zhenek [66]
2 years ago
14

A steam power plant is represented as a heat engine operating between two thermal reservoirs at 800 K and 300 K. The temperature

of the steam in the boiler is 550 K and the temperature of the saturated water in the condenser is 330 K. The rates of heat transfer in the boiler and condenser are 4 MW and 2 MW, respectively. Please answer the following.
Required:
a. Represent the devices present in the heat engine and include their name along with the data given in the problem.
b. If this steam power plant were to operate as a reversible heat engine, with the boiler and condenser temperatures, what would be its thermal efficiency?
c. Use your result from part (b) to determine if the actual steam power plant can achieve such thermal efficiency. Justify your answer.
d. For the actual steam power plant is the Clausius inequality satisfied? Show you computation and discuss whether your result agrees or disagrees with your answer in part (c).
Engineering
1 answer:
Sergeeva-Olga [200]2 years ago
4 0
Yeet is the answer .....
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A binary liquid system exhibits LLE at 25°C. Determine from each of the following sets of miscibility data estimates for paramet
Phoenix [80]

Answer:

(a) - A12 = A21 = 2.747

(b) - A12 = 2.148; A21 = 2.781

(c)-  A12 = 2.781; A21 = 2.148

Explanation:

(a) - x1(a) = 0.1 |  x2(a) = 0.9 | x1(b) = 0.9 | x2(b) = 0.1

LLE equations:

  • x1(a)*γ1(a) = x1(b)γ1(b)

        x2(a)*γ2(a) = x2(b)γ2(b)

  • A12 = A21 = 2.747

(b) -  x1(a) = 0.2 |  x2(a) = 0.8 | x1(b) = 0.9 | x2(b) = 0.1

LLE equations:

  • x1(a)*γ1(a) = x1(b)γ1(b)

        x2(a)*γ2(a) = x2(b)γ2(b)

  • A12 = 2.148; A21 = 2.781

(c) -  x1(a) = 0.1 |  x2(a) = 0.9 | x1(b) = 0.8 | x2(b) = 0.2

LLE equations:

  • x1(a)*γ1(a) = x1(b)γ1(b)

        x2(a)*γ2(a) = x2(b)γ2(b)

  • A12 = 2.781; A21 = 2.148
7 0
3 years ago
An existing building is suffering from cracks in the exterior walls. The investigating engineer wants to ensure that the foundat
jek_recluse [69]

Answer:

18 ft^{2}

Explanation:

Soil bearing pressure=\frac {Load}{Area}

Since we're given pressure of 2500 psf and load of 45000 pounds

The area=\frac {45000}{2500}=18

Therefore, the smallest area of safe footings should not be less than 18 ft^{2}

6 0
2 years ago
Oxygen combines with nitrogen in the air to form NOx at about
rusak2 [61]
B) Oxygen combines with nitrogen in the air to form NOx at about 2500 degrees Fahrenheit.
4 0
2 years ago
Read 2 more answers
The following is a list of metals and alloys:
viktelen [127]

Answer:

A) Gray cast iron

B) Aluminum

C) Titanium alloy

D) Tool steel

E) Titanium alloy

F) magnesium

G) Tungsten

5 0
2 years ago
Consider a Carnot refrigeration cycle executed in a closed system in the saturated liquid–vapor mixture region using 1.06 kg of
Alexxandr [17]

Answer:

P_m_i_n = 442KPA

Explanation:

We are given:

m = 1.06Kg

T_H = 1.2T_L

T = 22kj

Therefore we need to find coefficient performance or the cycle

COP_R = \frac {1}{(T_R/T_l) -1}

= \frac {1 }{1.2-1}

= 5

For the amount of heat absorbed:

Q_l = COP_R Wm

= 5 × 22 = 110KJ

For the amount of heat rejected:

Q_H = Q_L + W_m

= 110 + 22 = 132KJ

[tex[ q_H = \frac{Q_L}{m} [/tex];

= = \frac{132}{1.06}

= 124.5KJ

Using refrigerant table at hfg = 124.5KJ/Kg we have 69.5°c

Convert 69.5°c to K we have 342.5K

To find the minimum temperature:

T_L = \frac{T_H}{1.2};

T_L = \frac{342.5}{1.2}

= 285.4K

Convert to °C we have 12.4°C

From the refrigerant R -134a table at T_L = 12.4°c we have 442KPa

6 0
3 years ago
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