Pls help me answer my module
1 answer:
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Answer:
attached below
Explanation:
Answer:
A)
- Q ( kw ) for vapor = -1258.05 kw
- Q ( kw ) for liquid = -1146.3 kw
B )
- Q ( kj ) for vapor = -1258.05 kJ
- Q ( KJ ) for liquid = - 1146.3 KJ
Explanation:
Given data :
45.00 % mole of methane
55.00 % of ethane
attached below is a detailed solution
A) calculate - Q(kw)
- Q ( kw ) for vapor = -1258.05 kw
- Q ( kw ) for liquid = -1146.3 kw
B ) calculate - Q ( KJ )
- Q ( kj ) for vapor = -1258.05 kJ
- Q ( KJ ) for liquid = - 1146.3 KJ
since combustion takes place in a constant-volume batch reactor
Answer:
import java.util.Scanner;
public class SumVectorElements
{
public static void main(String[] args)
{
final int NUM_VALS = 4;
int[] origList = new int[NUM_VALS];
int[] offsetAmount = new int[NUM_VALS];
int i = 0;
origList[0] = 40;
origList[1] = 50;
origList[2] = 60;
origList[3] = 70;
offsetAmount[0] = 5;
offsetAmount[1] = 7;
offsetAmount[2] = 3;
offsetAmount[3] = 0;
/* Your solution goes here */
// Print the Sum of each element in the origList
// with the corresponding value in the
// offsetAmount.
for (i = 0; i < NUM_VALS; i++)
{
System.out.print((origList[i] + offsetAmount[i])+" ");
}
System.out.println("");
return;
}
}
Explanation: see attachment below
