5. Consider the LTI system defined by the differential equation (a) Draw the pole-zero plot for the system. Is the system stable
? (5 points) (b) Find the system’s impulse response h(t). (5 points) (c) Find the system’s output if the input signal is x(t) = cos(2t). (5 points) (d) Find the system’s output if the input is x(t) = e-t u(t). (10 points)
1 answer:
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Answer:
total time = 304.21 s
Explanation:
given data
y = 50% = 0.5
n = 1.1
t = 114 s
y = 1 - exp(-kt^n)
solution
first we get here k value by given equation
y = 1 - ...........1
put here value and we get
0.5 = 1 - e^{(-k(114)^{1.1})}
solve it we get
k = 0.003786 = 37.86 ×
so here
y = 1 -
1 - y =
take ln both side
ln(1-y) = -k ×
so
t = .............2
now we will put the value of y = 87% in equation with k and find out t
t =
total time = 304.21 s
Answer:
The correct answer is "".
Explanation:
Given:
Maximum load,
P = 50,000 N
Crack length,
a = 3mm
or,
= 3×10⁻³ m
Diameter,
d = 32 mm
As we know,
⇒ Maximum stress,
Now,
⇒ Fracture tougness,
On substituting the values, we get