A dog and a cat sit on a merry-go-round. The dog sits 0.3 m from the center. The cat sits 1.5 m from the center. The whole merry
1 answer:
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Answer:
The velocity is
Explanation:
From the question we are told that
The first distance is
The first speed is
The second distance is
The second speed is
Generally the time taken for first distance is
The time taken for second distance is
The total time is mathematically represented as
=>
=>
Generally the constant velocity that would let her finish at the same time is mathematically represented as
=>
=>
Answer:
Explanation:
Given that,
Weight of jet
W = 2.25 × 10^6 N
It is at rest on the run way.
Two rear wheels are 16m behind the front wheel
Center of gravity of plane 10.6m behind the front wheel
A. Normal force entered on the ground by front wheel.
Taking moment about the the about the real wheel.
Check attachment for better understanding
So,
Clock wise moment = anti-clockwise moment
W × 5.4 = N × 16
2.25 × 10^6 × 5.4 = 16•N
N = 2.25 × 10^6 × 5.4 / 16
N = 7.594 × 10^5 N
B. Normal force on each of the rear two wheels.
Using the second principle of equilibrium body.
Let the rear wheel normal be Nr and note, the are two real wheels, then, there will be two normal forces
ΣFy = 0
Nr + Nr + N — W = 0
2•Nr = W—N
2•Nr = 2.25 × 10^6 — 7.594 × 10^5
2•Nr = 1.491 × 10^6
Nr = 1.491 × 10^6 / 2
Nr = 7.453 × 10^5 N
