Answer:
[KI] = 0.25 M
Explanation:
Solute: KI
Mass of solute: 0.50 mol . 166 g / 1mol = 83 g
Our solution volume is 2L
Molarity is a kind of concentration, defined as the moles of solute contained in 1L of solution. It is the most common concentration for all solutions while there are any other kind, for example molality, mole fraction or ppm.
In this case molarity (mol/L) is 0.5 mol /2L = 0.25 M
In conclussion, solution is 0.25 molar whichs is the same to say, that 0.25 moles of potassium iodide are contained in 1L of solution.
With the data given, we can also make a rule of three:
2L of solution contain 0.5 moles of KI
Then, 1L of solution may contain (0.5 . 1) /2 = 0.25 moles of Ki
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(Missing in the question) solubility in g per 100 mL of water:
CdI2 86.2 (cold water) so,
-We will heat a saturation solution of CdI2 [86.2 g / 100 mL], by the effect of the heat the solution will be unsaturated and dissolve more CdI2 when reaching a high temperature. and let the solution cools again by itself and covers it well to make sure there is no dust in it. when it reaches back to the cold water temperature, we will find the solution is supersaturated and all the solute will stay dissolved.
Sorry I don't like science