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motikmotik
3 years ago
10

Consider the following equilibrium:

Chemistry
1 answer:
Ainat [17]3 years ago
7 0

<u>Answer: </u>The equation which is wrong is K_p=K_c(RT)^{-5}

<u>Explanation:</u>

For the given reaction:

4Fe(s)+3O_2(g)\rightarrow 2Fe_2O_3(s)

The expression for K_c\text{ and }K_p is given by:

K_c=\frac{1}{[O_2]^3}

K_p=\frac{1}{[O_2]^3}

The concentration of solids are taken to be 1, only concentration of gases and liquid states are taken. The pressure of only gases are taken.

Relationship between K_p\text{ and }K_c is given by the expression:

K_p=K_c\times (RT)^{\Delta n_g}

where,

\Delta n_g= number of moles of gaseous products - number of moles of gaseous reactants

R = gas constant

T= temperature

For the above reaction,

\Delta n_g = number of moles of gaseous products - number of moles of gaseous reactants = 0 - 3 = -3

Hence, the expression for K_p is:

K_p=K_c\times (RT)^{-3}

Therefore, the equation which is wrong is K_p=K_c(RT)^{-5}

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