Question

Calculate the heat change involved when 2.00 L of water is heated from 20.0/C to 99.7/C in

Answer 1

Answer:

666,480 Joules or 669.48 kJ

Explanation:

We are given;

• Volume of water as 2.0L or 2000 ml

but, density of water is 1 g/ml

• Therefore, mass of water is 2000 g

• Initial temperature as 20 °C
• Final temperature as 99.7° C

Required to determine the heat change

We know that ;

Heat change = Mass × Temperature change × specific heat

In this case;

Specific heat of water is 4.2 J/g°C

Temperature change is 79.7 °C

Therefore;

Heat change = 2000 g × 79.7 °C × 4.2 J/g°C

                      = 669,480 Joules 0r 669.48 kJ

Thus, the heat change involved is 666,480 Joules or 669.48 kJ