The acceleration of the boat is (eastward)
Explanation:
We can solve this problem by using Newton's second law, which states that:
F = ma (1)
where
F is the net force on a body
m is its mass
a is its acceleration
First of all, we have to find the net force acting on the boat. We have:
- The force of the motor, 100 N eastward
- The force of the air resistance, 60 N westward
So the net force is:
F = 100 N - 60 N = 40 N (eastward)
Now we can apply eq.(1), using:
F = 40 N
m = 20 kg (mass of the boat)
and solving for a, we find the acceleration:
And the direction is the same as the net force (eastward).
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consider east-west direction along x-axis and north-south direction along y-axis
from the diagram
A = Ax i + By j = - (0.40 Sin60) i + (0.40 Cos60) j = - 0.35 i + 0.20 j
B = Bx i + By j = - 0.50 i + 0 j
Net displacement is given as
D = A + B
D = (- 0.35 i + 0.20 j ) + (- 0.50 i + 0 j )
D = - 0.85 i + 0.2 j
magnitude of displacement is given as
|D| = sqrt((- 0.85)² + (0.2)²)
|D| = 0.87 km
direction of displacement is given as
θ = tan⁻¹(0.2/0.85)
θ = 13.5 deg north of west
Answer:
The new kinetic energy is 9 times of the initial kinetic energy.
Explanation:
The kinetic energy of an object is given by the formula as follows :
Where
m is mass and v is speed of the body
If the speed of the body is tripled. Let v' is the new speed, v' = 3v. The new kinetic energy is E' and it is given by :
Hence, the new kinetic energy is 9 times of the initial kinetic energy.