Hey there!
theoretical yield = (87* 100 ) / 60 = 145 g of phosphorous pentachloride
the reaction for this process is :
molar mass P2O5 => 239.2125 g/mol
molar mass P4 => 123.90 g/mol
molar mass Cl2 => 70.9060 g/mol
P4 + 5 Cl2 --------------> 2 P2Cl5
moles of P2O5 :
145 g / 239.2125 => 0.6062 moles of P2O5
Therefore:
moles of P4 = 0.6062 mol / 2 => 0.3031 moles
moles of Cl2 = 5/2 * 0.6062 mol = 1.5154 moles
mass of P4 ( phosphours ) = 0.3031 mol * 123.90 => 37.554 grams
mass of Cl2 ( chlorine ) = 1.5154 mol * 70.9060 => 107.45 grams
Hope That helps!
The brownish rock is a sedimentry rock was formed when things like sand, mud, or pebbles get laid down in layers. Eventually the layers are lithified.
The grey rock is a metamorphic rock and was when other rocks are changed because of heat or pressure. Earth movements can cause rocks to be deeply buried or squeezed. As a result, the rocks are heated and put under great pressure. They do not melt, but the minerals they contain are changed chemically, forming metamorphic rocks.
The red dots rock is an igneous rock. Igneous rock forms when hot, molten rock crystallizes and solidifies.
Explanation:
The limiting reagent (or limiting reactant or limiting agent) in a chemical reaction is a reactant that is totally consumed when the chemical reaction is completed. The amount of product formed is limited by this reagent, since the reaction cannot continue without it.
Na5Cl2
penta is 5, so 5 sodiums and di is 2, so 2 chloride
Answer:
1.09 grams
Explanation:
According to the following chemical equation:
HF + NaNO₃ -> HNO₃ + NaF
1 mol of hydrogen fluoride (HF) produces 1 mol of sodium fluoride (NaF). Thus, we first convert from mol to grams by using the molar mass (MM) of each compound:
MM(HF)= (1 g/mol x 1 H) + (19 g/mol x 1 F) = 20 g/mol HF
1 mol HF x 19.9 g/mol HF = 20 g
MM(NaF) = (23 g/mol x 1 Na) + (19 g/mol x 1 F) = 42 g/mol NaF
1 mol NaF x 42 g/mol NaF = 42 g
Thus, from 20 g of HF are produced 42 g of NaF ⇒ 20 g HF/42 g NaF. We multiply this stoichiometric ratio by the mass of NaF produced to calculate the required mass of HF:
20 g HF/42 g NaF x 2.3 g NaF = 1.09 g HF
Therefore, 1.09 grams of HF are necessary to produce 2.3 g of NaF.
