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Yakvenalex [24]
4 years ago
9

Which of the following rights is granted by the Fifth Amendment?

Chemistry
1 answer:
kondaur [170]4 years ago
6 0

"The Fifth Amendment protects individuals from being forced to incriminate themselves. ... The privilege against compelled self-incrimination is defined as "the constitutional right of a person to refuse to answer questions or otherwise give testimony against himself. ..."

-Google

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A battery changes chemical energy into _____.
Sophie [7]
It turns chemical into electricity 
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3 years ago
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_____________ is an acronym used to refer a family of iron alloys.
Daniel [21]

FeNi or NiFe is an acronym used to refer a family of iron alloys.

<h3>What is alloy?</h3>

An alloy is a mixture of chemical elements that contains at least one is a metal.

<h3>Alloy of iron</h3>

The alloy of iron-nickel can be abbreviated as FeNi, which implies iron-nickel.

where;

  • Fe stands for iron
  • Ni stands for Nickel

Thus, FeNi or NiFe is an acronym used to refer a family of iron alloys.

Learn more about iron alloys here: brainly.com/question/24842164

5 0
2 years ago
Which of the following chemical formulas contains the most molecules?
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C. 2Fe2O3 would be the correct answer!
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3 years ago
What parts are present in every chemical equation?
77julia77 [94]
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3 years ago
In a certain city, electricity costs $0.15 per kW·h. What is the annual cost for electricity to power a lamp-post for 6.00 hours
Vanyuwa [196]

(a) Power of bulb is 100 W, converting this into kW.

1 W=\frac{1}{1000}kW

Thus,

100 W =\frac{100}{1000}kW=0.1 kW

The bulb is used for 6 hours per day for a year, in 1 year there are 365 days thus, total hours will be:

t=6\times 365=2190 h

Electricity used will depend on power and number of hours as follows:

E=P\times t=0.1 kW\times 2190 h=219 kW.h

The cost of electricity is $0.15 per kW.h thus, cost of electricity for 219 kW.h will be:

Cost=\$ (219\times 0.15)=\$ 32.85

Therefore, annual cost of incandescent light bulb is \$ 32.85

(b) Power of bulb is 25 W, converting this into kW.

1 W=\frac{1}{1000}kW

Thus,

100 W =\frac{25}{1000}kW=0.025 kW

The bulb is used for 6 hours per day for a year, in 1 year there are 365 days thus, total hours will be:

t=6\times 365=2190 h

Electricity used will depend on power and number of hours as follows:

E=P\times t=0.025 kW\times 2190 h=54.75 kW.h

The cost of electricity is $0.15 per kW.h thus, cost of electricity for 54.75 kW.h will be:

Cost=\$ (54.75\times 0.15)=\$ 8.21

Therefore, annual cost of fluorescent bulb is \$ 8.21.

7 0
3 years ago
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