<h3>
Answer:</h3>
42960 years
<h3>
Explanation:</h3>
<u>We are given;</u>
- Remaining mass of C-14 in a bone is 0.3125 g
- Original mass of C-14 on the bone is 80.0 g
- Half life of C-14 is 5370 years
We are required to determine the age of the bone;
- Remaining mass = Original mass × 0.5^n , where n is the number of half lives.
Therefore;
0.3125 g = 80.0 g × 0.5^n
3.90625 × 10^-3 = 0.5^n
- Introducing logarithm on both sides;
log 3.90625 × 10^-3 = n log 0.5
Solving for n
n = log 3.90625 × 10^-3 ÷ log 0.5
= 8
- Therefore, the number of half lives is 8
- But, 1 half life is 5370 years
- Therefore;
Age of the rock = 5370 years × 8
= 42960 years
Thus, the bone is 42960 years old
Answer:
For the control experiment: 
of aqueous solution of erioglaucine has absorbance of 
From Lambert-Beer's law we know:
Here; e is the molar absorptivity coefficient of erioglaucine
l = length of cuvette in which the solution is taken = 
A sorbance by the erioglaucine = total absorbance - absorbance by distilled 
So; by putting the values in the above equation; we get:
So; 
The molar absorptivity coefficient of erioglaucine is 
The absorbance of erioglaucine in distilled water (contaminated with metal ions) is: 
The absorbance of distilled water is 
So; absorbance of erioglaucine itself is : 
Again using Lambert Beer law; we get:
c = 0.198/5.65 M = 0.035 M
The concentration of the erioglaucine is
Explanation:
Answer:
no ,its not necessary tht two objects have same volume have the same mass because the density of the material they are made up of can be different. mass and volume areindependent, two objects with thesame volume can have differentmasses. Therefore, the objects can have different densities.
Answer:
i think its b but i could be wrong
Explanation:
