M1V1 = M2V2
37.5 mL * 0.245M = 18.0 mL * x M
(37.5*0.245)/18 = x M
x = 0.510
0.510 M is the answer.
it is a postive ionnnnnnnnnnnnnnnnnnnnn
answer= 0.912 L or 912 mL
M(KClO3) = 122.55 g/mol
3.00 g KClO3 * 1 mol/122.55 g = 3.00/122.55 mol =0.02449 mol
2KCIO3(s)=2KCI(s) + 3O2(g)
from reaction 2 mol 3 mol
given 0.02449 mol x
x = 0.02449*3/2 =0.03673 mol O2
T = 24 + 273.15 = 297.15 K
PV = nRT
V= nRT/P = (0.03673 mol*0.082057 L*atm/K*mol*297.15 K)/0.982 atm =
= 0.912 L or 912 mL
Answer:
4.31 atm.
Explanation:
- We can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant,
T is the temperature of the gas in K.
- If n and V are constant, and have different values of P and T:
<em>(P₁T₂) = (P₂T₁)</em>
<em></em>
P₁ = 3.81 atm, T₁ = 25°C + 273 = 298 K,
P₂ = ??? atm, T₂ = 50°C + 273 = 323 K,
- Applying in the above equation
(P₁T₂) = (P₂T₁)
<em>∴ P₂ = (P₁T₂)/(T₁)</em> = (3.81 atm)(323 K)/(298 K) = <em>4.31 atm.</em>
Answer:
Explanation:
check the attachment for the propose neutral structure for each compound that is consistent with the data.
