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Triss [41]
2 years ago
12

The purpose of the salt bridge in an electrochemical cell is to ________. Question 10 options: provide oxygen to facilitate oxid

ation at the anode maintain electrical neutrality in the half-cells via migration of ions provide a means for electrons to travel from the anode to the cathode provide a means for electrons to travel from the cathode to the anode provide a source of ions to react at the anode and cathode
Chemistry
1 answer:
svetlana [45]2 years ago
8 0

Answer:The purpose of the salt bridge in an electrochemical cell is to <u>maintain electrical neutrality in the half-cells via migration of ions </u>

Explanation:

A salt bridge is a u-shaped tube or filter paper bridge type  laboratory device used to connect the oxidation and reduction half-cells of a galvanic/voltaic cell. it maintains electrical neutrality in the half cells thereby  preventing the cell from having imbalance of charges in the flow of electrons moving from one half cell to another.

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3.124mg of I-131 is present after 32.4 days.

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The time required for half of something to undergo a process: such as. a : the time required for half of the atoms of a radioactive substance to become disintegrated.

Half of the iodine-131 will still be present after 8.1 days.

The amount of iodine-131 will again be halved after 8.1 additional days, for a total of 8.1+8.1=16.2 days, reaching (1/2)(1/2)=1/4 of the initial amount.

The quantity of iodine-131 will again be halved after 8.1 more days, for a total of 16.2+8.1+8.1=32.4 days, to (1/4)(1/2)(1/2)=1/16 of the initial quantity.

If the original dose of iodine-131 was 50mg, the residual dose will be (50mg)*(1/16)=3.124mg after 32.4 days.

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Explanation:

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Which way will the reaction shift if the volume is cut in half? a. toward the reactants b. toward the products c. the reaction w
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The reaction will  shift toward the reactants if the volume is cut in half.

<h3 /><h3>Reactants </h3>

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1 year ago
What are nanochemicals and what are there uses?
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6 0
3 years ago
How many fluorine atoms bond with calcium to form calcium fluoride? one two three four five
Elena-2011 [213]
Calcium fluoride.
Ca is metal, F is non-metal, so they form ionic bond.
Ca as metal can form only positive ion. Ca in the second group, so the charge of Ca ion is 2+.   Ca²⁺
F is in the 17th group, so it has 7 electrons on the last level. It is non-metal, non-metal, so it has negative charge -(8-7)=-1. "8" because on the last level cannot be more than 8 electrons. F-ion is F¹⁻.

Ca²⁺  F¹⁻
Number of positive charges should be equal to number of negative charges,
Formula of calcium fluoride
CaF2.
2 atoms Fluorine bond with Calcium.
7 0
3 years ago
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