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FinnZ [79.3K]
3 years ago
12

The heat energy gained by the water in one minute is ?

Physics
1 answer:
kari74 [83]3 years ago
7 0
<span>fast-moving particles colliding with slow-moving particles</span>
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) A striker can give the ball an initial speed of 30m/s. Within what two elevation angles must he kick
sveticcg [70]

Answer:

  about 19.6° and 73.2°

Explanation:

The equation for ballistic motion in Cartesian coordinates for some launch angle α can be written ...

  y = -4.9(x/s·sec(α))² +x·tan(α)

where s is the launch speed in meters per second.

We want y=2.44 for x=50, so this resolves to a quadratic equation in tan(α):

  -13.6111·tan(α)² +50·tan(α) -16.0511 = 0

This has solutions ...

  tan(α) = 0.355408 or 3.31806

The corresponding angles are ...

  α = 19.5656° or 73.2282°

The elevation angle must lie between 19.6° and 73.2° for the ball to score a goal.

_____

I find it convenient to use a graphing calculator to find solutions for problems of this sort. In the attachment, we have used x as the angle in degrees, and written the function so that x-intercepts are the solutions.

5 0
2 years ago
Mary travelled 70 miles/hour due north. This is an example of what?
kolezko [41]
I believe this would be an example of Mary's velocity. We have her speed and direction which is all you need to find velocity.
4 0
2 years ago
Read 2 more answers
If the load on Pulley E is 20N, how much effort is needed to life it?
Mariana [72]
It would need to be over 20 because if the load of the Pulley E is 20 and the effort is 20, then they will be equal and the Pulley would not move, so your answer is at least 20
7 0
3 years ago
What is most likely to happen during deposition?
Iteru [2.4K]

Answer:

a person appears at a specified time and place and gives sworn testimony

Explanation:

Hope this helps

6 0
2 years ago
An 85-kg hiker climbs to the summit of Mount Mitchell in western North Carolina. During one 2.0-h period, the climber's vertical
Bas_tet [7]

Answer:

The change in gravitational potential energy of the climber-Earth system,\Delta E=4.49\times 10^5\ J

Explanation:

Given that,

Mass of the hiker, m = 85 kg

Time, t = 2 h

Vertical elevation of the climber, h = 540 m

We need to find the change in gravitational potential energy of the climber-Earth system. We know that due to change in position of an object, gravitational potential energy occurs. It is given by :

\Delta E=mgh\\\\\Delta E=85\times 9.8\times 540\\\\\Delta E=4.49\times 10^5\ J

So, the change in gravitational potential energy of the climber-Earth system is 4.49\times 10^5\ J. Hence, this is the required solution.  

5 0
3 years ago
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