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3 years ago

12

The heat energy gained by the water in one minute is ?

1 answer:

kari74 [83]3 years ago

7 0

<span>fast-moving particles colliding with slow-moving particles</span>

You might be interested in

The elbow is an example of a compound machine found in the human body. true or false

GenaCL600 [577]

The elbow is considered to be a lever, which is a simple machine. Other levers apart from the elbow are jaw, ankle, knee, etc.
This means that it is false that the <span>elbow is an example of a compound machine found in the human body.</span>

4 0

4 years ago

A radioactive nucleus has a half-life of 5*108 years. Assuming that a sample of rock (say, in an asteroid) solidified right afte

Gre4nikov [31]

Answer:

0.002

Explanation:

The half-life of the radioactive nucleus is related to its quantity, by the following equation:

$N_{t} = N_{0}2^{-t/t_{1/2}}$

<u>Where:</u>

<em>N(t): is the quantity of the radioactive nucleus at time t</em>

<em>N₀: is the initial quantity of the radioactive nucleus</em>

<em>t: is the time = 4.5x10⁹ years</em>

<em>t(1/2): is the half-life of the radioactive nucleus = 5x10⁸ years</em>

$\frac{N_{t}}{N_{0}} = 2^{-4.5 \cdot 10^{9} y/5 \cdot 10^{8} y} = 2 \cdot 10^{-3}$

Therefore, the fraction of the radioactive element in the rock today is 0.002.

I hope it helps you!

7 0

3 years ago

What is the relationship between kinetic and potential energy in a roller coaster.

sukhopar [10]

Answer:

Kinetic energy is energy that an object has as a result of its motion. All moving objects possess kinetic energy, which is determined by the mass and speed of the object. Potential energy is the energy an object has as a result of its position. Potential energy is stored energy that has not yet been released.

Explanation:

8 0

3 years ago

Read 2 more answers

A person has a far point of 50 cm. If he is wearing glasses 2 cm from the eyes, determine

Alla [95]

Answer:

The power will be "2.08 D".

Explanation:

According to the question,

The location of the image form lens,

$d_i=50-2$

$=48 \ cm$

We know that,

⇒ $\frac{1}{d_i} -\frac{1}{d_o} =\frac{1}{f}$

here,

$d_o$ = Object location

$d_i$ = Image location

$f$ = Focal length

On putting the values in the above expression, we get

⇒ $\frac{1}{48} -\frac{1}{\infty} =\frac{1}{f}$

$f=48 \ cm$

or,

$f=0.48 \ m$

hence,

The refractive power will be:

⇒ $P=\frac{1}{f}$

$=\frac{1}{0.48}$

$=2.08 \ D$

7 0

3 years ago

A golf course sprinkler system discharges water from a horizontal pipe at the rate of 7200 cm3/s. At one point in the pipe, wher

vichka [17]

Answer: $P_2=2.246\times 10^5 Pa$

Explanation:

Given

Flow rate $Q=7200 cm^3/s$

At one Point $r_1=4 cm$

$A_1=\frac{\pi d_1^2}{4}$

$A_1=\frac{\pi 64}{4}=16\pi cm^2$

$P_1=2.4\times 10^5 Pa$

At second Point

$r_2=2 cm$

$A_2=\frac{\pi d_2^2}{4}$

$A_2=4\pi cm^2$

Density of water $\rho =10^3 kg/m^3$

As Flow is constant therefore

$Q=A_1v_1=A_2v_2$

$v_1=\frac{Q}{A_1}=\frac{7200}{16\pi }=143.22 cm/s\approx =1.43 m/s$

$v_2=\frac{Q}{A_2}=\frac{7200}{4\pi }=572.88 cm/s\approx 5.72 m/s$

Applying Bernoulli's theorem

$P_1+\frac{\rho v_1^2}{2}+\rho gh_1=P_2+\frac{\rho v_2^2}{2}+\rho gh_2$

as pipe is horizontal therefore $h_1-h_2=0$

thus $P_2=P_1+\frac{\rho }{2}\left [ v_1^2-v_2^2\right ]$

$P_2=2.40\times 10^5+\frac{10^3}{2}\left [ 1.43^2-5.72^2\right ]$

$P_2=2.40\times 10^5-0.1533\times 10^5$

$P_2=2.246\times 10^5 Pa$

7 0

3 years ago