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Elan Coil [88]
3 years ago
8

After a displacement of 17 m, a train on a straight track is at the position xf = –2.5 m

Physics
2 answers:
EastWind [94]3 years ago
5 0

-19.5m

-19.5+17=-2.5m

padilas [110]3 years ago
3 0

Answer:

x_i = -19.5 m

Explanation:

As we know that the displacement is defined as the change in the position.

So we will have

displacement = x_f - x_i

here we know that

displacement = 17 m

initial position = ?

final position is given as

x_f = -2.5 m

so we have

(-2.5 m) - x_i = 17 m

x_i = -2.5 - 17

x_i = -19.5 m

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The total resistance of a 15-ohm, an 65-ohm and a 35-ohm resistor connected in parallel ​
yanalaym [24]

Answer:

I think its 9.0397 Ohms

Explanation:

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3 0
3 years ago
What is the flow rate of water in a pipe flowing full with an area of 0.3 m2 and velocity of 2.5 m/s?
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From the question,

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4 0
3 years ago
The magnetic field at the center of a 1.0-cm-diameter loop is 2.5 mT.
olga nikolaevna [1]

Answer:

(a) The current in the wire is 19.89 A

(b) The distance from the wire is 0.159 cm

Explanation:

Given;

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radius of the wire, r = 0.5 cm = 0.005 m

(a) The current in the wire is calculated as;

I = \frac{2Br}{\mu_0} \\\\I = \frac{2\times 2.5 \times 10^{-3} \times 0.005 }{4\pi \times 10^{-7} } \\\\I = 19.89 \ A

(b) The distance from the wire where the magnetic field is 2.5 mT is calculated as;

B = \frac{\mu_0 I}{2\pi d} \\\\where;\\\\d \ is \ the \ distance \ from \ the \  wire\\\\d = \frac{\mu_0 I}{2\pi B} = \frac{4 \pi \times 10^{-7} \times 19.89}{2\pi \times 2.5 \times 10^{-3}}  = 0.00159 \ m = 0.159 \ cm

6 0
3 years ago
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Calling Me the Earth's mass, Mv Venus mass, and d the distance between the two planets, the gravitational force between them is:
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so, correct answer is C).
7 0
3 years ago
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