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3 years ago

After a displacement of 17 m, a train on a straight track is at the position xf = –2.5 m

Physics

2 answers:

EastWind [94]3 years ago

5 0

-19.5m

-19.5+17=-2.5m

padilas [110]3 years ago

3 0

Answer:

$x_i = -19.5 m$

Explanation:

As we know that the displacement is defined as the change in the position.

So we will have

$displacement = x_f - x_i$

here we know that

displacement = 17 m

initial position = ?

final position is given as

$x_f = -2.5 m$

so we have

$(-2.5 m) - x_i = 17 m$

$x_i = -2.5 - 17$

$x_i = -19.5 m$

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A ball rolls off a desk at a speed of 2 m/s and lands 0.50 seconds later.

Hoochie [10]

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(a) The ball lands <u>1 m</u> ahead of the desk's base.

(b) The height of the desk is <u>1.225 m.</u>

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(a)

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Now, considering only the horizontal motion of the ball. The ball not under the influence of any force in the horizontal direction.

Therefore, the distance covered by the ball horizontally is given as:

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(b)

Now, consider only the vertical motion of the ball. The ball is under the influence of gravity.

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$y-y_0=u_{oy}t+\frac{1}{2}gt^2$

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$y_{0}\rightarrow \textrm{initial vertical position of ball}\\u_{oy}\rightarrow \textrm{initial vertical velocity}\\g\rightarrow \textrm{acceleration due to gravity}\\y\rightarrow \textrm{final position of ball vertically}$

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3 years ago

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