2H₂ + O₂ = 2H₂O
n(H₂)=m(H₂)/M(H₂)
n(H₂)=5g/2.0g/mol=2.5 mol
n(O₂)=m(O₂)/M(O₂)
n(O₂)=40g/32.0g/mol=1.25 mol
H₂ : O₂ = 2 : 1
2.5 : 1.25 = 2 : 1
n(H₂O)=n(H₂)=2n(O₂)=2.5 mol
m(H₂O)=n(H₂O)M(H₂O)
m(H₂O)=2.5mol*18.0g/mol=45.0 g
58kg
Explanation:
Given parameters:
Mass of bicycle = 8kg
Total force exerted = 191.4N
Acceleration = 2.9m/s²
Unknown:
Naomi's mass = ?
Solution:
Force is a product of mass and acceleration as sated in the second law of newton.
Force = mass x acceleration
Total force on the bicycle = total mass x acceleration
191.4 = (8 + k) 2.9
8 + k = = 66
K = 66 - 8 = 58kg
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Answer:
81.0°C
Explanation:
<em>Kb benzene = 2.5°C/m</em>
<em />
The addition of a solute to a pure solvent produce an elevation in boiling point regarding to boiling point of pure solvent. This phenomenon follows the equation:
ΔT = Kb×m×i
<em>where ΔT represents the increasing in boiling point, Kb is the elevation boiling point constant of the solvent (2.5°C/m for benzene), m is molality of solution (Moles solute / kg solvent) and i is Van't Hoff factor (1 for a non-electrolyte solute as naphthalene).</em>
<em />
Moles of 11.5g of naphthalene (Molar mass: 128.17g/mol) are:
11.5g × (1mol / 128.17g) =<em> 0.0897 moles of naphthalene in 250.0g = 0.250kg of benzene.</em>
Molality is:
0.0897 moles of naphthalene / 0.250kg of benzene = 0.359m
Replacing in the equation:
ΔT = Kb×m×i
ΔT = 2.5°C/m×0.359m×1
ΔT = 0.90°C
That means the solution prepared has an elevation in boiling point of 0.90°C. As boiling point of pure benzene is 80.10°C, boiling point of the solution is:
80.10°C + 0.90°C =
<h3>81.0°C</h3>
Answer:
It's (6.02214179×1023) / one mole of substance.
Neutralization happens or occur