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Over [174]
4 years ago
11

What variable represents specific heat in the equation q = mct?

Chemistry
1 answer:
Nata [24]4 years ago
5 0

The "c" represents in specific heat in this question.


Q is the total energy, m is the mass, c is the specific heat capacity, and t is the temperature change. This equation is the equation for calculating about the total energy given out of absorbed when a temperature of a substance changes.


For example, if we want to know how much heat is absorbed by 1 kg of water for it to rise by 10 degrees, we can calculate by using the specific heat of water, which is around 4200 J kg-1 °C-1. So the total heat absorbed would be 1 x 4200 x 10 = 42000 J.

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A, They Lower The Activation Energy.
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Predict the two most likely mechanisms for the reaction of 1-iodohexane with potassium tert-butoxide.
Rudiy27

Answer:

C) SN2 and E2

Explanation:

For this question, we have analyzed the <u>substrate</u> and the <u>base/nucleophile</u>. The substrate, in this case, is 1-iodohexane and the base/nucleophile is potassium tert-butoxide.

<u>Substrate</u>

<u />

In the 1-iodohexane the iodide "I" is bonded to a primary carbon (carbon 1). Therefore we will have a <u>primary substrate</u>. If we have a primary substrate an Sn1 can not take place. We can not have a <u>primary carbocation</u> due to this instability. So, we can disccard options A) and B).

<u>Base/nucleophile</u>

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In the potassium tert-butoxide we have an ionic compound. A positive charge is placed in the potassium atom a negative charge is placed in the oxygen of the ter-butoxide ion. So, we will have a <u>strong base</u> (a molecule with the ability to remove electrons) and a <u>strong nucleophile</u> (a molecule with ability to bond with an electrophile). With all this in mind, w<u>e can not have an E1 reaction</u>.

With both analyses, the answer is C).

See figure 1

I hope it helps!

6 0
3 years ago
Help please!!!!!!!!!
Hatshy [7]

Answer:

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3 0
3 years ago
What is the density of air at 75 F and latm pressure? Express in lbm/ft3 and kg/m3
ser-zykov [4K]

Answer : The density of air in lbm/ft^3 and kg/m^3 is, 0.0743lbm/ft^3 and 1.19kg/m^3 respectively.

Explanation :

PV=nRT\\\\PV=\frac{m}{M}RT\\\\P=\frac{m}{V}\frac{RT}{M}\\\\P=\rho \frac{RT}{M}\\\\\rho=\frac{PM}{RT}

where,

P = pressure of air = 1 atm

V = volume of air

T = temperature of air = 297 K

The conversion used for the temperature from Fahrenheit to degree Celsius is:

^oC=(^oF-32)\times \frac{5}{9}

^oC=(75-32)\times \frac{5}{9}=24^oC

The conversion used for the temperature from degree Celsius to Kelvin is:

K=273+^oC

K=273+24=297K

n = number of moles

m = mass of air

M = average molar mass of air = 28.97 g/mole

\rho = density of air = ?

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the above formula, we get:

\rho=\frac{PM}{RT}

\rho=\frac{(1atm)\times (28.97g/mole)}{(0.0821L.atm/mol.K)\times (297K)}

\rho=1.19g/L

Now we have to calculate density in lbm/ft^3.

Conversion used :

1g/L=0.0624lbm/ft^3

So,

1.19g/L=\frac{1.19g/L}{1g/L}\times 0.0624lbm/ft^3=0.0743lbm/ft^3

The density of air in lbm/ft^3 is, 0.0743lbm/ft^3

Now we have to calculate density in kg/m^3.

Conversion used :

1g/L=1kg/m^3

So,

1.19g/L=1.19kg/m^3

The density of air in kg/m^3 is, 1.19kg/m^3

8 0
3 years ago
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