What variable represents specific heat in the equation q = mct?
1 answer:
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Answer:
C) SN2 and E2
Explanation:
For this question, we have analyzed the <u>substrate</u> and the <u>base/nucleophile</u>. The substrate, in this case, is 1-iodohexane and the base/nucleophile is potassium tert-butoxide.
<u>Substrate</u>
<u />
In the 1-iodohexane the iodide "I" is bonded to a primary carbon (carbon 1). Therefore we will have a <u>primary substrate</u>. If we have a primary substrate an Sn1 can not take place. We can not have a <u>primary carbocation</u> due to this instability. So, we can disccard options A) and B).
<u>Base/nucleophile</u>
<u />
In the potassium tert-butoxide we have an ionic compound. A positive charge is placed in the potassium atom a negative charge is placed in the oxygen of the ter-butoxide ion. So, we will have a <u>strong base</u> (a molecule with the ability to remove electrons) and a <u>strong nucleophile</u> (a molecule with ability to bond with an electrophile). With all this in mind, w<u>e can not have an E1 reaction</u>.
With both analyses, the answer is C).
See figure 1
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Answer : The density of air in and
is,
and
respectively.
Explanation :
where,
P = pressure of air = 1 atm
V = volume of air
T = temperature of air = 297 K
The conversion used for the temperature from Fahrenheit to degree Celsius is:
The conversion used for the temperature from degree Celsius to Kelvin is:
n = number of moles
m = mass of air
M = average molar mass of air = 28.97 g/mole
= density of air = ?
R = gas constant = 0.0821 L.atm/mol.K
Now put all the given values in the above formula, we get:
Now we have to calculate density in .
Conversion used :
So,
The density of air in is,
Now we have to calculate density in .
Conversion used :
So,
The density of air in is,