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lisabon 2012 [21]
3 years ago
6

Based on physical properties, which of these substances is an ionic compound? Explain your reasoning.

Chemistry
1 answer:
Bas_tet [7]3 years ago
4 0

Answer:

ExplanBased on physical properties, which of these substances is an ionic compound? Explain your reasoning.

A. Hair Gel

B. Silver Breacelet

C. Motor Oil

D. Baking SodaBased on physical properties, which of these substances is an ionic compound? Explain your reasoning.

A. Hair Gel

B. Silver Breacelet

C. Motor Oil

D. Baking SodaBased on physical properties, which of these substances is an ionic compound? Explain your reasoning.

A. Hair Gel

B. Silver Breacelet

C. Motor Oil

D. Baking SodaBased on physical properties, which of these substances is an ionic compound? Explain your reasoning.

A. Hair Gel

B. Silver Breacelet

C. Motor Oil

D. Baking Sodaation:

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If a plane is traveling300 mph how long will it take to travel 1800 miles
bonufazy [111]
My calculations say it'll take 600 hours???
5 0
3 years ago
A chemist must dilute of aqueous sodium carbonate solution until the concentration falls to . He'll do this by adding distilled
Mademuasel [1]

The question is incomplete, complete question is :

A chemist must dilute 73.9 mL of 400 mM aqueous sodium carbonate  solution until the concentration falls to 125 mM . He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits.

Answer:

The final volume of the solution will be 0.236 L.

Explanation:

Concentration of sodium carbonate solution before dilution =M_1= 400 mM

Volume of sodium carbonate solution before dilution = V_1=73.9 mL

Concentration of sodium carbonate solution after dilution =M_2= 125 mM

Volume of sodium carbonate solution after dilution = V_2=?

Dilution equation is given by:

M_1V_1=M_2V_2

V_2=\frac{M_1V_1}{M_2}

V_2=\frac{400 mM\times 73.9 mL}{125 mM}= 236.48 mL\approx 236 mL

1 mL = 0.001 L

236 mL = 0.236 L

The final volume of the solution will be 0.236 L.

3 0
3 years ago
The direction of movement of the cold front shown in the figure at left is _____.
Mice21 [21]

Answer:

northwest

Explanation:

Cmon man adleast try before you ask it on brainly or else you will never get any smarter

7 0
3 years ago
Read 2 more answers
How many grams of liquid CF2Cl2 are needed to cool 156 g of water from 42.9 to 20.5 °C? The specific heat of water is 4.184 J/(g
SashulF [63]

To cool 156 g of water from 42.9 °C to 20.5 °C, 101 g of CF₂Cl₂ are required.

CF₂Cl₂ is a refrigerant. When it is evaporated, it absorbs heat from water, which cools.

<h3>What is evaporation?</h3>

Evaporation is a type of vaporization that occurs on the surface of a liquid as it changes into the gas phase.

  • Step 1: Calculate the heat released by water.

We will use the following expression.

Qw = c × m × ΔT = (4.184 J/g.°C) × 156 g × (20.5 °C - 42.9 °C)

Qw = -14.6 kJ

where,

  • Qw is the heat released by water.
  • c is the specific heat of water.
  • m is the mass of water.
  • ΔT is the change in the temperature of water.

If water releases 14.6 kJ of heat, CF₂Cl₂ absorbs 14.6 kJ of heat (Qr = 14.6 kJ).

  • Step 2: Calculate the mass of the refrigerant required.

We will use the following expression.

Qr = ΔH°evap × m

m = Qr/ΔH°evap = 14.6 kJ / (0.144 kJ/g) = 101 g

where,

  • Qr is the heat absorbed by the refrigerant.
  • ΔH°evap is the heat of vaporization of the refrigerant.
  • m is the mass of the refrigerant.

To cool 156 g of water from 42.9 °C to 20.5 °C, 101 g of CF₂Cl₂ are required.

Learn more about evaporation here: brainly.com/question/25310095

4 0
2 years ago
The pattern of__ is visualized on X-ray film by autoradiography.​
posledela

Answer:

The pattern of decay emission is visualized on X-ray film by auto-radiography.

Explanation:

The image on the x-ray are auto-radiography or the nuclear emission that has been produced as a result of the decay emission because of the gamma particles or the beta particles which comes from a radioactive substance.  These auto-radiography are available as the digital image as a result of recent development of gas detectors or because of the rare earth phosphor imaging system. Some of the can be studied microscopically for silver granules this method is called as micro- auto-radiography.

4 0
2 years ago
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