(a) Differentiate the position vector to get the velocity vector:
<em>r</em><em>(t)</em> = (3.00 m/s) <em>t</em> <em>i</em> - (4.00 m/s²) <em>t</em>² <em>j</em> + (2.00 m) <em>k</em>
<em>v</em><em>(t)</em> = d<em>r</em>/d<em>t</em> = (3.00 m/s) <em>i</em> - (8.00 m/s²) <em>t</em> <em>j</em>
<em></em>
(b) The velocity at <em>t</em> = 2.00 s is
<em>v</em> (2.00 s) = (3.00 m/s) <em>i</em> - (16.0 m/s) <em>j</em>
<em></em>
(c) Compute the electron's position at <em>t</em> = 2.00 s:
<em>r</em> (2.00 s) = (6.00 m) <em>i</em> - (16.0 m) <em>j</em> + (2.00 m) <em>k</em>
The electron's distance from the origin at <em>t</em> = 2.00 is the magnitude of this vector:
||<em>r</em> (2.00 s)|| = √((6.00 m)² + (-16.0 m)² + (2.00 m)²) = 2 √74 m ≈ 17.2 m
(d) In the <em>x</em>-<em>y</em> plane, the velocity vector at <em>t</em> = 2.00 s makes an angle <em>θ</em> with the positive <em>x</em>-axis such that
tan(<em>θ</em>) = (-16.0 m/s) / (3.00 m/s) ==> <em>θ</em> ≈ -79.4º
or an angle of about 360º + <em>θ</em> ≈ 281º in the counter-clockwise direction.
The units of G must be C. m³ / ( kg s² )
<h3>Further explanation</h3>
Newton's gravitational law states that the force of attraction between two objects can be formulated as follows:
<em>F = Gravitational Force ( Newton )</em>
<em>G = Gravitational Constant ( 6.67 × 10⁻¹¹ Nm² / kg² )</em>
<em>m = Object's Mass ( kg )</em>
<em>R = Distance Between Objects ( m )</em>
Let us now tackle the problem !
To find unit of Gravitational Constant can be carried out in the following way:
![{[N]}= G\frac{{[kg]}{[kg]}}{{[m^2]}}](https://tex.z-dn.net/?f=%7B%5BN%5D%7D%3D%20G%5Cfrac%7B%7B%5Bkg%5D%7D%7B%5Bkg%5D%7D%7D%7B%7B%5Bm%5E2%5D%7D%7D)
![{[kg ~ m / s^2]}= G \frac{{[kg^2]}}{{[m^2]}}](https://tex.z-dn.net/?f=%7B%5Bkg%20~%20m%20%2F%20s%5E2%5D%7D%3D%20G%20%5Cfrac%7B%7B%5Bkg%5E2%5D%7D%7D%7B%7B%5Bm%5E2%5D%7D%7D)
![G = \frac{{[kg ~ m / s^2]}{[m^2]}} {{[kg^2]} }](https://tex.z-dn.net/?f=G%20%3D%20%5Cfrac%7B%7B%5Bkg%20~%20m%20%2F%20s%5E2%5D%7D%7B%5Bm%5E2%5D%7D%7D%20%7B%7B%5Bkg%5E2%5D%7D%20%7D)
![G = \frac{{[kg ~ m^3 / s^2]}} {{[kg^2]} }](https://tex.z-dn.net/?f=G%20%3D%20%5Cfrac%7B%7B%5Bkg%20~%20m%5E3%20%2F%20s%5E2%5D%7D%7D%20%7B%7B%5Bkg%5E2%5D%7D%20%7D)
![G = \frac{{[m^3 / s^2]}} {{[kg]} }](https://tex.z-dn.net/?f=G%20%3D%20%5Cfrac%7B%7B%5Bm%5E3%20%2F%20s%5E2%5D%7D%7D%20%7B%7B%5Bkg%5D%7D%20%7D)
![\boxed {G = \frac{{[m^3]}} {{[kg ~ s^2]} }}](https://tex.z-dn.net/?f=%5Cboxed%20%7BG%20%3D%20%5Cfrac%7B%7B%5Bm%5E3%5D%7D%7D%20%7B%7B%5Bkg%20~%20s%5E2%5D%7D%20%7D%7D)
The unit of G must be 
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Gravitational Fields
Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant
Answer:
x= 9.53 ounces
Explanation:
Given that
Mean ,μ= 9 ounces
Standard deviation ,σ=0.8 ounces
He wants to sell only those potatoes that are among the heaviest 25%.
P=25% = 0.25
When P= 0.25 then Z=0.674
Lest take x is the the minimum weight required to be brought to the farmer's market.
We know that
x = Z . σ + μ
x= 0.674 ₓ 0.8 + 9 ounces
x= 9.53 ounces
Temperature and rate of evaporation are proportional to each other. Surface area: As the surface area increases, the rate of evaporation increases. The surface area and rate of evaporation are proportional to each other. Humidity: The rate of evaporation decreases with an increase in humidity.
