1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zlopas [31]
3 years ago
6

What are the three components of soil texture? Hurry please help!

Chemistry
1 answer:
tiny-mole [99]3 years ago
5 0

Answer: sand, silt, and clay.

You might be interested in
This is how fluorine appears in the periodic table. A green box has F at the center and 9 above. Below it says fluorine and belo
Oksana_A [137]
1. Atomic weight of fluorine

2. Number of proton and neutrons found in the nucleus of the element

3. And every number uniquely identifies each of the the elements
8 0
3 years ago
Formula for Tricarbon heptabromide.
DiKsa [7]
I believe it would be Au^4Cl8
7 0
3 years ago
Determine el PH y el % de disociación de una solución de ácido débil, sabiendo que se disuelven 20 gramos del ácido (masa molar=
IceJOKER [234]

Answer:

pH = 4.27. Porcentaje de disociación: 0.03%

Explanation:

El pH de un ácido débil, HX, se obtiene haciendo uso de su equilibrio:

HX(aq) ⇄ H⁺(aq) + X⁻(aq)

Donde la constante de equilibrio, Ka, es

Ka = 1.65x10⁻⁸ = [H⁺] [X⁻] / [HX]

Como los iones H⁺ y X⁻ vienen del mismo equilibrio podemos decir:

[H⁺] = [X⁻]

[HX] es:

20g * (1mol/55g) = 0.3636moles / 2.100L = 0.1732M

Reemplazando es Ka:

1.65x10⁻⁸ = [H⁺] [H⁺] / [0.1732M]

2.858x10⁻⁹ = [H⁺]²

5.35x10⁻⁵M = [H⁺]

pH = -log[H⁺]

<h3>pH = 4.27</h3>

El porcentaje de disociacion es [X⁻] / [HX] inicial * 100

Reemplazando

5.35x10⁻⁵M / 0.1732M * 100

<h3>0.03%</h3>
5 0
2 years ago
10. Given the reaction:
andrey2020 [161]

Answer:

B hope help you stay happy

5 0
3 years ago
How much heat (in Joules) is needed to raise the temperature of 257g of ethanol (cethanol=2.4 J/g°C) by 49.1°C?
Sonbull [250]

Answer:

Q = 30284.88 j

Explanation:

Given data:

Mass of ethanol = 257 g

Cp = 2.4 j/g.°C

Chnage in temperature = ΔT = 49.1°C

Heat required = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree.

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

Now we will put the values in formula.

Q = 257 g× 2.4 j/g.°C × 49.1 °C

Q = 30284.88 j

8 0
3 years ago
Other questions:
  • Calculate the number of oxygen atoms in 2.00 moles of Mn2O7
    15·1 answer
  • Please help me! This is too hard!?
    12·1 answer
  • When the pH of 0.10 m HClO2(aq) was measured, it was found to be 1.2. a. What are the values of Ka and pKa of chlorous acid? b.
    7·1 answer
  • Which of the following statements about photophosphorylation is FALSE? Energy from oxidation reactions is used to generate ATP f
    14·1 answer
  • 23.495 g sample of aqueous waste leaving a fertilizer manufacturer contains ammonia. The sample is diluted with 72.311 g of wate
    6·1 answer
  • HELP PLZZZZ plz A PLZ plz
    10·1 answer
  • Helppppppp meeeeeeeeeeeee
    11·2 answers
  • PLEASE HELP WILL GIVE BRAINLIEST
    7·1 answer
  • How much work is done by a 35-watt light bulb if it is on for 1,320 seconds?
    8·1 answer
  • If 82.5 mol of an ideal gas occupies 10.5 l at 317 k, what is the pressure of the gas?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!