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2 years ago

Give the characteristic of a first order reaction having only one reactant.

Chemistry

1 answer:

Slav-nsk [51]2 years ago

6 0

Answer:

As the first order reaction depends on (a uni-molecular reaction) the concentration of only one reactant.

And the rate law of the reaction of first order with a reactant A is:

rate = K[A]^-1

when K is the rate constant.

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What is needed to burn the candle (reactant)?

Alexus [3.1K]

Answer:

wax, candlewick, and oxygen

Explanation:

The burning of the candle is both a physical as well as a chemical change. The reactants are the substances or the raw materials that are required for a reaction to the process. In the process of burning a candle, the reactants are the fuel which includes wax and wick, and oxygen which is found in the air. The products found at the end of the reaction are carbon dioxide and water vapor.

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3 years ago

Heat energy is _____ when it moves from one room to another.

MArishka [77]

Hello,

Thanks for posting your question here on brainly.

There are 3 ways heat energy can move: Radiation, conduction, and convection.

However, your answer to this is most likely conduction

hope this helps:)

please let me know if it's correct.

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2 years ago

_H3PO4 + _HCl --->_PCl5 + _H2O

Slav-nsk [51]

Dennis g studio and I don't have any money

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2 years ago

Help me it’s science

Nezavi [6.7K]

Bb
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3 years ago

Read 2 more answers

2.00 L of 0.800 M NaNO3 must be prepared from a solution known to be 2.50 M in concentration.How many mL are required? Plus don'

Morgarella [4.7K]

Answer:

1.36 × 10³ mL of water.

Explanation:

We can utilize the dilution equation. Recall that:

$\displaystyle M_1V_1= M_2V_2$

Where M represents molarity and V represents volume.

Let the initial concentration and unknown volume be M₁ and V₁, respectively. Let the final concentration and required volume be M₂ and V₂, respectively. Solve for V₁:

$\displaystyle \begin{aligned} (2.50\text{ M})V_1 &= (0.800\text{ M})(2.00\text{ L}) \\ \\ V_1 & = 0.640\text{ L} \end{aligned}$

Therefore, we can begin with 0.640 L of the 2.50 M solution and add enough distilled water to dilute the solution to 2.00 L. The required amount of water is thus:
$\displaystyle 2.00\text{ L} - 0.640\text{ L} = 1.36\text{ L}$

Convert this value to mL:
$\displaystyle 1.36\text{ L} \cdot \frac{1000\text{ mL}}{1\text{ L}} = 1.36\times 10^3\text{ mL}$

Therefore, about 1.36 × 10³ mL of water need to be added to the 2.50 M solution.

8 0

2 years ago