Question

Potassium carbonate dissolves as follows:

Answer 1

The 0.25 volume in liters of 1.0 M $K_{2}CO_{3}$ solution is required to provide 0.5 moles of $K$(aq).

Calculation,

The Potassium carbonate dissolves as follows:

$K_{2}CO_{3}(s)$ → $2K(aq) +$$CO_{3}^{-2} (aq)$

The mole ratio is 1: 2

It means, the 1 mole $K_{2}CO_{3}$ required to form 2 mole of $K$(aq).

To provide 0.5 mole of $K$(aq) = 1 mole ×0.5 mole /2 mole required by $K_{2}CO_{3}$.

To provide 0.5 mole of $K$(aq) ,0.25 mole required by $K_{2}CO_{3}$.

The morality of  $K_{2}CO_{3}$ = 1 M = number of moles / volume in lit

The morality of  $K_{2}CO_{3}$ =   1 M = 0.25 mole/ volume in lit

Volume in lit = 0.25 mole / 1 M = 0.25 mole/mole/lit = 0.25 lit

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