Answer:
k=320N/m
Explanation:
Step one:
given data
Let the initial/equilibrum position be x
mass m1= 0.2kg
F1= 0.2*10= 2N
elongation e= 9.5cm= 0.095m
mass m2=1kg
F2=1*10= 10N
elongation e= 12cm= 0.12m
Step two:
From Hooke's law, which states that provided the elastic limits of a material is not exceeded the extention e is proportional to applied Force F
F=ke
2=k(0.095-a)
2=0.095k-ka----------1
10=k(0.12-a)
10=0.12k-ka----------2
solving equation 1 and 2 simultaneously
10=0.12k-ka----------2
- 2=0.095k-ka----------1
8=0.025k-0
divide both side by 0.025
k=8/0.025
k=320N/m
<span>=1330 ft^2 x (1m^2/3.25 ft^2)
=124 m^2
</span>
A pressure system is a relative peak or lull in the sea level pressure distribution. The surface pressure at sea level varies minimally, with the lowest value measured 87 kilopascals (26 inHg) and the highest recorded 108.57 kilopascals (32.06 inHg). High- and low-pressure systems evolve due to interactions of temperature differentials in the atmosphere, temperature differences between the atmosphere and water within oceans and lakes, the influence of upper-level disturbances jargon as well as the amount of solar heating or radiational cooling an area receives. Pressure systems cause weather experienced locally. Low-pressure systems are associated with clouds and precipitation that minimize temperature changes through the day, whereas high-pressure systems normally associated with dry weather and mostly clear skies with larger diurnal temperature changes due to greater radiation at night and greater sunshine during the day. Pressure systems are analyzed by those in the field of meteorology within surface weather maps.
Answer: 10.67
Explanation:
First, we needed to calculate the radius and this will be:
= Diameter / 2
= 0.900km / 2
= 0.450km
Since s = 3.00miles, we need to convert it to kilometers and this will be:
1mile = 1.6km
3 miles = 3 × 1.6km = 4.8km
Radians = s/r = 4.8/0.45 = 10.67
Answer:
Therefore the capacitance of the capacitor is 2.38 * 10⁻⁵F
Explanation:
We apply the concepts related to Power and energy stored in a capacitor.
By definition we know that power is represented as
Where,
E= Energy
t = time
to find the Energy we have,
With the energy found we can know calculate the Capacitance in a capacitor through the energy for capacitor equation, that is
Therefore the capacitance of the capacitor is 2.38 * 10⁻⁵F
