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Contact [7]
4 years ago
6

Suppose a sound wave and a light wave have the same frequency.

Physics
2 answers:
dedylja [7]4 years ago
5 0

Answer:

The light wave has a longer wavelength and has the greater speed.

Explanation:

light has a far more greater speed than sound. The speed of sound in air is about 343m/s while that of light is around  3 *10^{8}m/s

wavelength (λ) =\frac{V}{f}

since the frequencies of sound and light are same from the question, the wavelength would depend on the magnitude of their velocities. Light with a higher speed would have a longer wavelength.

vagabundo [1.1K]4 years ago
4 0

Answer:

The light wave has a longer wavelength and has the greater speed.

Explanation:

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How to calculate the angle of a resultant<br>​
stiv31 [10]

Answer:

The direction angle θ of the resultant in the Polar (positive) specification is then θ = α + 60°. The Law of Cosines is used to calculate the magnitude (r) and the Law of Sines is used to calculate the angle (α).

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3 years ago
Trees in the mid-west change colors and lose their leaves in the cooler parts of the year.
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3 years ago
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Stopping distance of vehicles When brakes are applied to a moving vehicle, the distance it travels before stopping is called sto
DochEvi [55]

Answer:

Stopping distance = 40m

Explanation:

Given the following :

Initial speed of vehicle before applying brakes = 72km/hr

Converting km/hr to m/s:

72km/hr = [(72 * 1000)m] / (60 * 60)

72km/hr = 72,000m / 3600s

72km/hr = 20m/s

Deceleration after applying brakes (-a) (negative acceleration) = - 5m/s^2

From the 3rd equation of motion:

v^2 = u^2 + 2as

Where v = final Velocity ; u= Initial Velocity ; a = acceleration and s = distance

Final velocity when the car stops will be 0

Therefore ;

v^2 = u^2 + 2as

0 = 20^2 + 2(-5)(s)

0 = 400 - 10s

10s = 400

s = 400/10

s = 40m

Therefore, the stopping distance of the car = 40 meters

7 0
3 years ago
A real image is four times as far from a lens as is theobject.
saveliy_v [14]

Answer:

1.25 focal lengths

Explanation:

The lens equation states that:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

f is the focal length

p is the object distance

q is the image distance

In this problem, the image is 4 times as far from the lens as is the object: this means that

q=4p

If we substitute this into the lens equation and we rearrange it, we get

\frac{1}{f}=\frac{1}{p}+\frac{1}{4p}=\frac{4+1}{4p}=\frac{5}{4p}\\p=\frac{5}{4}f=1.25 f

so, the object distance measured in focal lengths is

1.25 focal lenghts

3 0
3 years ago
To study torque experimentally, you apply a force to a beam. One end of the beam is attached to a pivot that allows the beam to
natali 33 [55]

Answer:

  1. Resulting torque =  (ryFz - rzFy) i +(rzFx - rxFz) j+(rxFy - ryFx) k
  2. Magnitude of resulting torque  = 3.84 Nm
  3. Angular acceleration = = 0.0086877 rad/s² rad/s²

Explanation:

It is given that:

I = 442 kg˙m2

rx = 0.76 m, ry = 0.035 m, rz = 0.015 m,

Fx = 3.6 N, Fy = -2.8 N, Fz = 4.4 N

F = Fx i + Fy j + Fz               (equation 1)

r =  rx i + ry j + rz k               (equation 2)

(a) Torque

T = r * F               (equation 3)

by putting equation 1 and 2 into equation 3, we have;

Torque= r x F

           = (rx i +ry j +rz k) x (Fx i + Fy j +Fz k )

           = (ryFz - rzFy) i +(rzFx - rxFz) j+(rxFy - ryFx) k

Therefore,

Resulting torque =  (ryFz - rzFy) i +(rzFx - rxFz) j+(rxFy - ryFx) k

b) Magnitude of the torque

Resulting torque =  (ryFz - rzFy) i +(rzFx - rxFz) j+(rxFy - ryFx) k

=(0.025 x 2.2 - (0.035 x (-1.2))) i +(0.035 x (-7.8)) - 2.19 x 2.2) j+(2.19 x 1.2 - 0.025 - (-7.8)) k

= (0.055 - 0.042) i + (0.273 - 4.818) j + (-2.628 -0.195) k

= (0.013) i - (-4.545) j + (-2.433) k

Magnitude of resulting torque = √0.013² + 4.545² - 2.433²

                                                 =√14.751

                                                 = 3.84 Nm

c) Angular acceleration

Since

angular acceleration = torque/moment of inertia

                                  = 3.84/ 442

                                 = 0.0086877 rad/s²

Hence,

  1. Resulting torque =  (ryFz - rzFy) i +(rzFx - rxFz) j+(rxFy - ryFx) k
  2. Magnitude of resulting torque  = 3.84 Nm
  3. Angular acceleration = = 0.0086877 rad/s² rad/s²

To learn more about Torque, use the given link:

brainly.com/question/19247046?referrer=searchResults

#SPJ4

3 0
1 year ago
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