Answer:
8.91 J
Explanation:
mass, m = 8.20 kg
radius, r = 0.22 m
Moment of inertia of the shell, I = 2/3 mr^2
= 2/3 x 8.2 x 0.22 x 0.22 = 0.265 kgm^2
n = 6 revolutions
Angular displacement, θ = 6 x 2 x π = 37.68 rad
angular acceleration, α = 0.890 rad/s^2
initial angular velocity, ωo = 0 rad/s
Let the final angular velocity is ω.
Use third equation of motion
ω² = ωo² + 2αθ
ω² = 0 + 2 x 0.890 x 37.68
ω = 8.2 rad/s
Kinetic energy,

K = 0.5 x 0.265 x 8.2 x 8.2
K = 8.91 J
A. Diagram A
B. Diagram C & D
C. Diagram B
D. Diagram C & D
E. Diagram B
F. Diagram C & D
These are simplified representations of an object's body and the force vectors acting on it. Some of the main forces that are involve are normal force, friction, push or pull and gravity.
This resistance current is directly proportional to voltage and inversely proportional to resistance. In other words, as the voltage increases, so does the current. Hope this helps !!
Answer:
The detailed calculations are shown below;
Explanation:
a)The maximum acceleration of the particle:
It is seen that the maximum change in velocity is at the time between 8s to 10s.
Maximum acceleration: 
= 
= 10 m/
b) The deceleration of the particle
The velocity of particle is decreased after 10s so,
deceleration = - 
= - 6.67 m/
c)The total distance traveled by the particle = Area under the curve
=
* 4*20 + 4*20 +
* 2*20+ 2*20+
* 40*16
= 290 m
d)The average velocity of the particle = 
= 
= 18.12 m/s