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3 years ago

14

the gravity force between Mars and an object near Earth's surface as much lower than the force between an object on Earth surfac

e of Earth if the speaking of a hammer when dropped increase from 0.0 m / s to 15.0 m / s and 4.04 seconds what is the acceleration due to the gravity force of the surface of Mars

1 answer:

erma4kov [3.2K]3 years ago

3 0

<u>The acceleration:</u> is defined as the change of the velocity in 1 second.

In symbols

$a = \frac{V_{f}-V_{i} }{t}$

where:

$V_{f}$ : the final velocity
$V_{i}$ : the initial velocity
t : the time if the change

In our problem:

$a = \frac{15-0 }{4.04}=3.713 m/s^2$

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<u>Capacitance</u>

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$\displaystyle X_c^2=Z^2-R^2=\left(\frac{\sqrt{2}V}{I_p}\right)^2-R^2$

Or, equivalently

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$\displaystyle X_c=\sqrt{\frac{2\cdot 18^2}{0.00065^2}-15000^2}$

$X_c=36176.34\ \Omega$

The capacitance is now

$\displaystyle C=\frac{1}{226194.67\cdot 36176.34}=1.22\cdot 10^{-10}\ F$

The radius of the plates is

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The separation between the plates is

$\displaystyle d=\frac{8.85\cdot 10^{-12} \cdot \pi\cdot 0.09^2}{1.22\cdot 10^{-10}}$

$d=0.00184\ m$

$\boxed{d=1.84\ mm}$

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