B. Scientific claims can be verified through observation and experimentation, while pseudoscientific claims cannot. At least I think it is right.
Answer:
42.2 moles of H3PO4
Explanation:
The equation of the reaction is:
P2O5(s) + 3 H2O(l) ⟶ 2 H3PO4.
First we must obtain the number of moles of P2O5 from
Number of moles of P2O5= reacting mass of P2O5/molar mass of P2O5
Molar mass of P2O5= 141.9445 g/mol
Number of moles= 3000g/141.9445 g/mol = 21.1 moles of P2O5
From the reaction equation;
1 mole of P2O5 yields 2 moles of H3PO4
21.1 moles of P2O5 will yield 21.1 ×2/ 1 = 42.2 moles of H3PO4
A mineral is a naturally occurring inorganic element or compound having an orderly internal structure and characteristic chemical composition, crystal form, and physical properties. ... A rock is an aggregate of one or more minerals, or a body of undifferentiated mineral matter.
Answer: 50%
Explanation:
The number of electron pairs are 2 for hybridization to be 
and the electronic geometry of the molecule will be linear.
1. percentage of s character in sp hybrid orbital =
2. percentage of s character in 
hybrid orbital =
3. percentage of s character in 
hybrid orbital =
Thus percentage of s-character in an sp hybrid is 50%.
Answer:
1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate
Explanation:
Step 1: Data given
Mass of sodium bicarbonate = 2.7 grams
Step 2: The balanced equation
HCl + NaHCO3 ⇔ NaCl + H2O + CO2
Step 3: Calculate moles NaHCO3
moles NaHCO3 =2.7 g / 84 g/mol= 0.032 moles
Step 4: Calculate moles HCl
For 1 mol NaHCO3 we need 1 mol HCl
For 0.032 moles NaHCO3 = 0.032 moles HCl
Step 5: Calculate mass HCl
Mass HCl = moles HCl * molar mass HCl
mass HCl = 0.032 * 36.46 g/mol= 1.17 grams
1.17 grams of HCl can neutralize 2.7 grams sodium bicarbonate
